MySql 1248 - Every derived table must have its own alias

 

执行一个sql语句,报错:1248 - Every derived table must have its own alias

提示说每一个衍生出来的表,必须要有自己的别名

 

执行子查询的时候,外层查询会将内层的查询当做一张表来处理,所以我们需要给内层的查询加上别名

 

 错误的:

select count(*)
from(
    select  
    FROM_UNIXTIME(`user_task`.`CREATE_TIMESTAMP`, "%Y-%m-%d") 
    FROM
    r_user_task `user_task`
    LEFT JOIN
    e_task `task` ON `user_task`.`TASK_ID` = `task`.`ID`
    where `user_task`.`COMPLETE_STATUS` = "1" and `user_task`.`user_id` = 175286
    group by FROM_UNIXTIME(`user_task`.`CREATE_TIMESTAMP`, "%Y-%m-%d") 
) 

 

正确的sql,应该加上别名,如下:

select count(*)
from(
    select  
    FROM_UNIXTIME(`user_task`.`CREATE_TIMESTAMP`, "%Y-%m-%d") 
    FROM
    r_user_task `user_task`
    LEFT JOIN
    e_task `task` ON `user_task`.`TASK_ID` = `task`.`ID`
    where `user_task`.`COMPLETE_STATUS` = "1" and `user_task`.`user_id` = 175286
    group by FROM_UNIXTIME(`user_task`.`CREATE_TIMESTAMP`, "%Y-%m-%d") 
) as t

 

 

参考:

https://blog.csdn.net/cao478208248/article/details/28122113

 

posted @ 2018-05-31 17:54  裸奔的太阳  阅读(6327)  评论(0编辑  收藏  举报