实验三
task1
源代码
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#include <windows.h>
#define N 80
void print_text(int line, int col, char text[]); 
void print_spaces(int n); 
void print_blank_lines(int n); 
int main() {
  int line, col, i;
  char text[N] = "hi, April~";
  srand(time(0)); 
  for(i = 1; i <= 10; ++i) {
    line = rand() % 25;
    col = rand() % 80;
    print_text(line, col, text);
    Sleep(1000); 
    }
  return 0;
}
void print_spaces(int n) {
  int i;
  for(i = 1; i <= n; ++i)
  printf(" ");
}
void print_blank_lines(int n) {
  int i;
  for(i = 1; i <= n; ++i)
  printf("\n");
}
void print_text(int line, int col, char text[]) {
  print_blank_lines(line-1); 
  print_spaces(col-1); 
  printf("%s", text); 
}
运行结果截图

结论
随机生成10次行数和列数,在对应位置输出hi,April~
task2.1
源代码
#include <stdio.h>
long long fac(int n); 
int main() {
	int i, n;
	printf("Enter n: ");
	scanf("%d", &n);
	for (i = 1; i <= n; ++i)
	printf("%d! = %lld\n", i, fac(i));
	return 0;
}
long long fac(int n) {
	static long long p = 1;
        printf("p = %lld\n", p);
	p = p * n;
	return p;
}
运行结果截图

task2.2
源代码
#include <stdio.h>
	int func(int, int); 
	int main() {
	int k = 4, m = 1, p1, p2;
	p1 = func(k, m); 
	p2 = func(k, m); 
	printf("%d, %d\n", p1, p2);
	return 0;
}
int func(int a, int b) {
	static int m = 0, i = 2;
	i += m + 1;
	m = i + a + b;
	return m;
}
运行结果截图

task3
源代码
#include <stdio.h>
long long func(int n);
int main() {
	int n;
	long long f;
	while (scanf("%d", &n) != EOF) {
	f = func(n);
	printf("n = %d, f = %lld\n", n, f);
}
	return 0;
}
long long func(int n){
	int i;
	long long m=0;
	for(i=1;i<=n;i++){
		m=(m+1)*2-1;
	}
	return m;
}
运行结果截图

task4
源代码
#include <stdio.h>
int func(int n,int m);
int main(){
    int n,m;
    while(scanf("%d%d",&n,&m)!=EOF){
        printf("n=%d,m=%d,ans=%d\n",n,m,func(n,m));
        
    }    
    return 0;
}
int func(int n,int m){
if (n==m || m==0){
return 1;}
else if(n<m){return 0;
}
return func(n-1,m)+func(n-1,m-1);
}
运行结果截图

task5
源代码
#include <stdio.h>
double mypow(int x, int y); 
int main() 
{
    int x, y;
    double ans;
    while(scanf("%d%d", &x, &y) != EOF)
     {
        ans = mypow(x, y); 
        printf("%d的%d次方: %g\n\n", x, y, ans);
    }
    return 0;
}
double mypow(int x, int y)
{
    int i;
    double ans=1.0;
    if(y>=0)
    {
        for(i=1;i<=y;i++)
            ans=ans*x;
        return ans;
    }
    else
    {
        for(i=1;(i+y)<=0;i++)
            ans=ans/x;
        return ans;
    }
}
运行结果截图

task5.2
源代码
#include <stdio.h>
double mypow(int x, int y); 
int main() 
{
    int x, y;
    double ans;
    while(scanf("%d%d", &x, &y) != EOF)
     {
        ans = mypow(x, y); 
        printf("%d的%d次方: %g\n\n", x, y, ans);
    }
    return 0;
}
double mypow(int x, int y)
{
    double ans=1;
    if(y==0)
    ans=1;
    if(y>0)
        ans=ans*x*mypow(x,y-1);
    if(y<0)
        ans=ans/x*mypow(x,y+1);
    return ans;
}
运行结果截图

task6
源代码
#include<stdio.h>
#include<math.h>
void hanoi(int n,char from,char temp,char to);
void move(int n,char from,char to);
int main()
{
    int n;
    while(scanf("%d", &n) != EOF)
    {
        hanoi(n,'A','B','C');
        printf("一共移动了%g次\n\n",pow(2,n)-1);
    }
    return 0;
}
void hanoi(int n,char from,char temp,char to)
{
    if(n==1)
        move(n,from,to);
    else
    {
        hanoi(n-1,from,to,temp);
        move(n,from,to);
        hanoi(n-1,temp,from,to);
    }
}
void move(int n,char from,char to)
{
    printf("%d:%c-->%c\n",n,from,to);
}
运行结果截图

task7
源代码
#include<stdio.h>
int is_prime(int n);
int main()
{
    int n,i;
    for(n=4;n<=20;n+=2)
    {
        for(i=2;i<=(n/2);i++)
        {
            if(is_prime(i)&&is_prime(n-i))
            {
                printf("%d = %d + %d\n",n,i,n-i);
                break;
            }
        }
    }
    return 0;
 } 
 int is_prime(int n)
 {
     int i,flag=1;
     for(i=2;i<n;i++)
     {
         if(n%i==0)
             flag=0;
     }
     return flag;
 }
运行结果截图

task8
源代码
#include <stdio.h>
#include <math.h>
long func(long s);
int main() 
{
    long s, t;
    printf("Enter a number: ");
    while (scanf("%ld", &s) != EOF) 
    {
        t = func(s); 
        printf("new number is: %ld\n\n", t);
        printf("Enter a number: ");
    }
    return 0;
}
long func(long s)
{
    long ans=0;
    long x,i=1;
    while(s!=0)
    {
        x=s%10,s=s/10;
        if(x%2!=0)
        {
            ans=ans+x*i;
            i=i*10;
        }    
    }
    return ans;
}
运行结果截图

 
                    
                 
                
            
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浙公网安备 33010602011771号