实验三
task1
源代码
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#include <windows.h>
#define N 80
void print_text(int line, int col, char text[]);
void print_spaces(int n);
void print_blank_lines(int n);
int main() {
int line, col, i;
char text[N] = "hi, April~";
srand(time(0));
for(i = 1; i <= 10; ++i) {
line = rand() % 25;
col = rand() % 80;
print_text(line, col, text);
Sleep(1000);
}
return 0;
}
void print_spaces(int n) {
int i;
for(i = 1; i <= n; ++i)
printf(" ");
}
void print_blank_lines(int n) {
int i;
for(i = 1; i <= n; ++i)
printf("\n");
}
void print_text(int line, int col, char text[]) {
print_blank_lines(line-1);
print_spaces(col-1);
printf("%s", text);
}
运行结果截图

结论
随机生成10次行数和列数,在对应位置输出hi,April~
task2.1
源代码
#include <stdio.h>
long long fac(int n);
int main() {
int i, n;
printf("Enter n: ");
scanf("%d", &n);
for (i = 1; i <= n; ++i)
printf("%d! = %lld\n", i, fac(i));
return 0;
}
long long fac(int n) {
static long long p = 1;
printf("p = %lld\n", p);
p = p * n;
return p;
}
运行结果截图

task2.2
源代码
#include <stdio.h>
int func(int, int);
int main() {
int k = 4, m = 1, p1, p2;
p1 = func(k, m);
p2 = func(k, m);
printf("%d, %d\n", p1, p2);
return 0;
}
int func(int a, int b) {
static int m = 0, i = 2;
i += m + 1;
m = i + a + b;
return m;
}
运行结果截图

task3
源代码
#include <stdio.h>
long long func(int n);
int main() {
int n;
long long f;
while (scanf("%d", &n) != EOF) {
f = func(n);
printf("n = %d, f = %lld\n", n, f);
}
return 0;
}
long long func(int n){
int i;
long long m=0;
for(i=1;i<=n;i++){
m=(m+1)*2-1;
}
return m;
}
运行结果截图

task4
源代码
#include <stdio.h>
int func(int n,int m);
int main(){
int n,m;
while(scanf("%d%d",&n,&m)!=EOF){
printf("n=%d,m=%d,ans=%d\n",n,m,func(n,m));
}
return 0;
}
int func(int n,int m){
if (n==m || m==0){
return 1;}
else if(n<m){return 0;
}
return func(n-1,m)+func(n-1,m-1);
}
运行结果截图

task5
源代码
#include <stdio.h>
double mypow(int x, int y);
int main()
{
int x, y;
double ans;
while(scanf("%d%d", &x, &y) != EOF)
{
ans = mypow(x, y);
printf("%d的%d次方: %g\n\n", x, y, ans);
}
return 0;
}
double mypow(int x, int y)
{
int i;
double ans=1.0;
if(y>=0)
{
for(i=1;i<=y;i++)
ans=ans*x;
return ans;
}
else
{
for(i=1;(i+y)<=0;i++)
ans=ans/x;
return ans;
}
}
运行结果截图

task5.2
源代码
#include <stdio.h>
double mypow(int x, int y);
int main()
{
int x, y;
double ans;
while(scanf("%d%d", &x, &y) != EOF)
{
ans = mypow(x, y);
printf("%d的%d次方: %g\n\n", x, y, ans);
}
return 0;
}
double mypow(int x, int y)
{
double ans=1;
if(y==0)
ans=1;
if(y>0)
ans=ans*x*mypow(x,y-1);
if(y<0)
ans=ans/x*mypow(x,y+1);
return ans;
}
运行结果截图

task6
源代码
#include<stdio.h>
#include<math.h>
void hanoi(int n,char from,char temp,char to);
void move(int n,char from,char to);
int main()
{
int n;
while(scanf("%d", &n) != EOF)
{
hanoi(n,'A','B','C');
printf("一共移动了%g次\n\n",pow(2,n)-1);
}
return 0;
}
void hanoi(int n,char from,char temp,char to)
{
if(n==1)
move(n,from,to);
else
{
hanoi(n-1,from,to,temp);
move(n,from,to);
hanoi(n-1,temp,from,to);
}
}
void move(int n,char from,char to)
{
printf("%d:%c-->%c\n",n,from,to);
}
运行结果截图

task7
源代码
#include<stdio.h>
int is_prime(int n);
int main()
{
int n,i;
for(n=4;n<=20;n+=2)
{
for(i=2;i<=(n/2);i++)
{
if(is_prime(i)&&is_prime(n-i))
{
printf("%d = %d + %d\n",n,i,n-i);
break;
}
}
}
return 0;
}
int is_prime(int n)
{
int i,flag=1;
for(i=2;i<n;i++)
{
if(n%i==0)
flag=0;
}
return flag;
}
运行结果截图

task8
源代码
#include <stdio.h>
#include <math.h>
long func(long s);
int main()
{
long s, t;
printf("Enter a number: ");
while (scanf("%ld", &s) != EOF)
{
t = func(s);
printf("new number is: %ld\n\n", t);
printf("Enter a number: ");
}
return 0;
}
long func(long s)
{
long ans=0;
long x,i=1;
while(s!=0)
{
x=s%10,s=s/10;
if(x%2!=0)
{
ans=ans+x*i;
i=i*10;
}
}
return ans;
}
运行结果截图

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