leetcode刷题_PYTHON(22):链表(22) 回文链表

 

 

 

 

class Solution:
    def isPalindrome(self, head: ListNode) -> bool:
        vals = []
        current_node = head
        while current_node is not None:
            vals.append(current_node.val)
            current_node = current_node.next
        return vals == vals[::-1]

作者：LeetCode-Solution
链接：https://leetcode-cn.com/problems/palindrome-linked-list/solution/hui-wen-lian-biao-by-leetcode-solution/
来源：力扣（LeetCode）
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