fastjson将json格式字符串转成list集合
1.gameListStr = "[{"gameId":"1","gameName":"哈哈"},{"gameId":"2","gameName":"呵呵"}]";
2. List<Game> gameList = JSONObject.parseArray(gameListStr, Game.class);
public class Game { public String gameId; public String gameName; public String getGameId() { return gameId; } public void setGameId(String gameId) { this.gameId = gameId; } public String getGameName() { return gameName; } public void setGameName(String gameName) { this.gameName = gameName; } }
本文来自博客园,作者:King-DA,转载请注明原文链接:https://www.cnblogs.com/qingmuchuanqi48/p/11622399.html

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