SQL 中常用的功能函数，自定义的功能行数

在SQL Server指定的数据库中，有Programmability目录，在这个目录下，有存储过程，有功能函数。

 

 

set ANSI_NULLS ON
set QUOTED_IDENTIFIER ON
go

ALTER function   [dbo].[fn_10to36]   ( 
	@i   int 
) 
returns   varchar(30) 
as 
begin 

	declare  @r  varchar(30) 
	set   @r= '' 

	declare  @m  int 
	declare  @s  int 
	set   @s=@i 
	while   @s> =36 
	begin 
		set   @m=@s   %   36 
		set   @r=case   when   @m <10   then   cast(@m   as   varchar)   
			else   cast(char(ascii( 'A')+@m-10)   as   varchar)   end+@r 
		set   @s=@s/36 
	end 
		if   @s> 0   or   (@s=0   and   @r= '') 
			set   @r=case   when   @s <10   then   cast(@s   as   varchar)   
		else   cast(char(ascii( 'A')+@s-10)   as   varchar)   end+@r 
	return   @r 
end 　　

 

比如上述，执行

is not a recognized function name.

 上面报错，因为要加dbo.[function], 

 

select dbo.[fn_10to36_ByJasmine] (101) 即可

 

 

 

下面是36wei转10位

set ANSI_NULLS ON
set QUOTED_IDENTIFIER ON
go


ALTER function   [dbo].[fn_36to10]   ( 
@str   varchar(30) 
) 
returns   int
as 
begin 

declare @returnValue int
select @returnValue = 0
declare @str36 varchar(32)
declare @subWork varchar(1)
declare @workIndex int
select @str36 = '123456789ABCDEFGHIJKLMNOPQRSTUVWSYZ'

declare @len int
declare @i int
select @i = 1
select @len = datalength(@str)

while (@i <= @len)
begin
	select @subWork = SUBSTRING(@str, @i, 1) 
	select @workIndex = charindex( @subWork, @str36)
	select @returnValue = @returnValue + (@workIndex * power(36, @len-@i))
	select @i = @i + 1
end

return   @returnValue 
end 

　　

 

前面再带个参数的

CREATE FUNCTION [DBO].[FN_10TO36] (
@I INT,@B VARCHAR(10))
RETURNS VARCHAR(30)
AS 
BEGIN

DECLARE @R VARCHAR(30)
SET @R=''

DECLARE @M INT 
DECLARE @S INT
SET @S=@I
WHILE @S>=36
BEGIN
SET @M=@S %36 ----取余
SET @R=CASE WHEN @M<10 THEN CAST(@M AS VARCHAR)
ELSE CAST(CHAR(ASCII('A')+@M-10)AS VARCHAR) END +@R
SET @S=@S/36   -----取值
END
IF @S>0 OR (@S=0 AND @R='')
SET @R=CASE WHEN @S<10 THEN CAST(@S AS VARCHAR)
ELSE CAST(CHAR(ASCII('A')+@S-10) AS VARCHAR ) END +@R
RETURN @B+RIGHT('0000'+@R,5)
END