Javascript 如何能简短优雅地实现 sleep 函数?

async function test() {
  console.log('Hello')
  await sleep(1000)
  console.log('world!')
}

function sleep(ms) {
  return new Promise(resolve => setTimeout(resolve, ms))
}

test()

posted @ 2021-07-30 22:22  qcjdp  阅读(55)  评论(0编辑  收藏  举报

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