import java.util.*;
public class Solution {
// Parameters:
// numbers: an array of integers
// length: the length of array numbers
// duplication: (Output) the duplicated number in the array number,length of duplication array is 1,so using duplication[0] = ? in implementation;
// Here duplication like pointor in C/C++, duplication[0] equal *duplication in C/C++
// 这里要特别注意~返回任意重复的一个,赋值duplication[0]
// Return value: true if the input is valid, and there are some duplications in the array number
// otherwise false
public boolean duplicate(int numbers[],int length,int [] duplication) {
if(length <= 1){
return false;
}
boolean[] temp = new boolean[length];
for(int i : numbers){
if(temp[i] == false){
temp[i]=true;
}
else{
duplication[0] = i;
return true;
}
}
return false;
}
}