day26 Pyhton select功能语句实现
一.查询语句功能实现
select id,name where age > '20'
name_value = {'id':0,'name':1,'age':2,'phone':3,'job':4}
sql = 'select id,name where age > 20'#sql = input('>>>').strip()
def format_sql(sql):
sql = sql.replace('select', '') # 'select name , age where age > 20' 替换select为空
sql = sql.replace(' ', '') # 'name,agewhereage>20' 去掉空格
col, con = sql.split('where') # col = 'name,age',con = 'age>20' 以where切割,得到两个参数
if '*' in col:
col_lst = name_value.keys() #'*'代表所有的key值'id,'name','age,phone,'job
else:
col_lst = col.split(',') # col_lst = ['name','age'] 得到name,age
return col_lst,con # col_lst = ['name','age'] con = 'age>20'
def read_file():#遍历文件里的内容
with open('userinfo', encoding='utf-8') as f:
for line in f:
line_lst = line.strip().split(',')
yield line_lst#返回一行内容
def show(con,col_l,symbol,condition):#con = age>20 col_l = ['name' ,symbo为l条件比较符号为>,condition为'int(con_value) < int(line_lst[num])
con_name, con_value = con.split(symbol) # con_name = 'age',con_value = 20 以条件比较符号>进行切割
for line_lst in read_file():#调用read_file()生成器函数
num = name_value[con_name] #age的值是2 num = 2
if eval(condition):#eval使字符串里的代码运行 int(con_value) < int(line_lst[num]
for col in col_l: # ['name','age']
print(line_lst[name_value[col]], end=' ')
#name_value[col]为2,3,取出line_lst列表索引为2,3的值
print()
def select(sql):
# sql = 'select name,age where age>20'
col_l, con = format_sql(sql) # 调用format_sql函数 col_l = ['name', 'age'],con = age>20
if '>' in con:#判断比较符号是什么
show(con,col_l,'>','int(con_value) < int(line_lst[num])')#调用show()函数,
if '<' in con:
show(con, col_l, '<', 'int(con_value) > int(line_lst[num])')
if '=' in con:
show(con, col_l, '=', 'con_value == line_lst[num]')
if 'like' in con:
show(con, col_l, 'like', 'con_value in line_lst[num]')
# 先判断一下是否是查操作
if sql.startswith('select'):
# 是查找操作
select(sql)#调用select函数
else:
print('是其他操作')
class Base: def __init__(self): self.func() def func(self): print('in base') class Son(Base): def func(self): print('in son')#in son s = Son()

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