python实现三级菜单联动

程序需求

1. 能够显示每级菜单

2. 每级菜单中能够返回到上级

3. 每级菜单中能够退出

代码实现

 1 menu = {
 2     "湖北省":{
 3         "武汉市":["江岸区", "江汉区", "汉阳区"],
 4         "荆门市":["东宝区", "京山县" ],
 5         "荆州市":["沙市区", "荆州区","江陵县"]
 6     },
 7     "河北省":{
 8         "保定市":["定州市", "唐县", "徐水区", "清苑区"],
 9         "唐山市":["路南区", "路北区", "遵化市"]
10     },
11     "山东省":{
12         "淄博市":["张店区", "淄川区"],
13         "青岛市":["市南区", "市北区", "黄岛区"],
14         "济南市":["历下区", "市中区", "天桥区", "章丘区"],
15         "烟台市":["莱州市", "蓬莱市", "海阳市"]
16     }
17 }
18 
19 while True:
20     for key in current_layer:
21         print(key)
22     choice = input(">>>:").strip()
23     if len(choice) == 0:
24         continue
25     if choice in current_layer:
26         parent_list.append(current_layer)  # 修改之前的层数
27         print(parent_list)
28         current_layer = current_layer[choice]  # 修改之后的子层
29     elif choice == "b":
30         if parent_list:
31             current_layer = parent_list.pop()
32     else:
33         print("无此项！")

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思路来源

来源网络自学

posted on 2018-03-15 10:37 Artisan正传阅读(508) 评论(0) 收藏举报