Django ORM基本操作:
# 1.增删改查
create、delete、update、all、filter
# 2. 一般:
#id>1
models.UserInfo.objects.filter(id__gt=1)
#id>=1
models.UserInfo.objects.filter(id__gte=1)
#id<1
models.UserInfo.objects.filter(id__lt=1)
#id<=1
models.UserInfo.objects.filter(id__lte=1)
#id in [1,2,3]
models.UserInfo.objects.filter(id__in=[1,2,3])
#id in [1,2] ,切片,要头不要尾
models.UserInfo.objects.filter(id__range=[1,3])
#以什么开头
models.UserInfo.objects.filter(name__startswith='xxxx')
#包含
models.UserInfo.objects.filter(name__contains='xxxx')
#不包括id=1
models.UserInfo.objects.exclude(id=1)
# 3. 排序
#正序
user_list = models.UserInfo.objects.all().order_by('id')
#反序,当id一样的情况下,name正序排序
user_list = models.UserInfo.objects.all().order_by('-id','name')
# 4. 分组
from django.db.models import Count,Sum,Max,Min
#以ut_id为组,查询ut_id和组内id个数。(简记:以部门为组,查询部门的id和有多少人)
#v.query是打印出sql语句
v =models.UserInfo.objects.values('ut_id').annotate(xxxx=Count('id'))
print(v.query)#select ut_id,count(id) as xxxx from UserInfo group_by ut_id
v =models.UserInfo.objects.values('ut_id').annotate(xxxx=Count('id')).filter(xxxx__gt=2)
print(v.query)
v =models.UserInfo.objects.filter(id__gt=2).values('ut_id').annotate(xxxx=Count('id')).filter(xxxx__gt=2)
print(v.query)
# 5. F,更新时用于获取原来的值,原来的age都加1
from django.db.models import F
models.UserInfo.objects.all().update(age=F("age")+1)
# 6. Q,用于构造复杂查询条件
# 应用一:
from django.db.models import Q
#id>1
models.UserInfo.objects.filter(Q(id__gt=1))
#id=8 或 id=2
models.UserInfo.objects.filter(Q(id=8) | Q(id=2))
#id=8 和 id=2
models.UserInfo.objects.filter(Q(id=8) & Q(id=2))
# 应用二:
q1 = Q()
q1.connector = 'OR'
q1.children.append(('id__gt', 1))
q1.children.append(('id', 10))
q1.children.append(('id', 9))
q2 = Q()
q2.connector = 'OR'
q2.children.append(('c1', 1))
q2.children.append(('c1', 10))
q2.children.append(('c1', 9))
q3 = Q()
q3.connector = 'AND'
q3.children.append(('id', 1))
q3.children.append(('id', 2))
q1.add(q3,'OR')
con = Q()
con.add(q1, 'AND')
con.add(q2, 'AND')
models.UserInfo.objects.filter(con)
(id>1 or id=10 or id=9 or (id=1 and id=2)) and (c1=1 or c1=10 or c1=9)
# 7. extra, 额外查询条件以及相关表,排序
models.UserInfo.objects.extra(self, select=None, where=None, params=None, tables=None, order_by=None, select_params=None)
# a. 映射
# select
# select_params=None
# select 此处 from 表
# b. 条件
# where=None
# params=None,
# select * from 表 where 此处
# c. 表
# tables
# select * from 表,此处
# d. 排序
# order_by=None
# select * from 表 order by 此处
models.UserInfo.objects.extra(
select={'newid':'select count(1) from app01_usertype where id>%s'},
select_params=[1,],
where = ['age>%s'],
params=[18,],
order_by=['-age'],
tables=['app01_usertype']
)
#相当于
"""
select
app01_userinfo.id,
(select count(1) from app01_usertype where id>1) as newid
from app01_userinfo,app01_usertype
where
app01_userinfo.age > 18
order by
app01_userinfo.age desc
"""
# 8. 原生SQL语句,记得在settings.py中设置好DATABASES,
和在__init__.py中把MySQLdb修改为通过pymysql模块来连接数据库。
有个问题:结果是元组,无法在模板里面进行类似row.id这样的替换,
这种替换是需要字典或者字典列表才可以进行的,而且
cursor = connection.cursor(cursor=pymysql.cursors.DictCursor)报错,
所以无法获取字典或者字典列表这样的结果。
from django.db import connection, connections
cursor = connection.cursor() # connection是默认数据库
cursor = connections['db2'].cursor()#指定数据库
cursor.execute("""SELECT * from auth_user where id = %s""", [1])
row = cursor.fetchone()#结果是元组:(k,v)
row_list = cursor.fetchall()#结果是元组((k1,v1),(k2,v2))
# 9. 其他操作
http://www.cnblogs.com/wupeiqi/articles/6216618.html