2021年5月26日
sssd
摘要： def solution(nn): result = [1] cur = 2 chou = [2,3,5] while len(result) < nn: print(cur, result) if cur in chou: result.append(cur) cur += 1 continue 阅读全文
posted @ 2021-05-26 20:56 哈哈哈喽喽喽 阅读(57) 评论(0) 推荐(0)
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摘要： def solution(nn): result = [1] cur = 2 chou = [2,3,5] while len(result) < nn: print(cur, result) if cur in chou: result.append(cur) cur += 1 continue 阅读全文
posted @ 2021-05-26 20:55 哈哈哈喽喽喽 阅读(60) 评论(0) 推荐(0)