sssd

def solution(nn):
    result = [1]
    cur = 2
    chou = [2,3,5]
    while len(result) < nn:
        print(cur, result)
        if cur in chou:
            result.append(cur)
            cur += 1
            continue

        for i in chou:
            if int(cur / i) in result:
                result.append(cur)
                cur += 1
                break
    return result[-1]
    #

  

posted @ 2021-05-26 20:56  哈哈哈喽喽喽  阅读(57)  评论(0)    收藏  举报