不用基于交换的排序求一个数组排序后的相邻最大差值

#include<iostream>
#include<algorithm>
#include<limits.h>
using namespace std;
vector<int>maxs,mins;
vector<bool>st;
int where(int num, int n, int mi, int mx){
    return (num-mi)*n/(mx-mi);
}
int vmax(vector<int>& arr, int n){
    int mx=INT_MIN,mi=INT_MAX;
    for(int i=0;i<n;i++){
        mx=max(mx,arr[i]);
        mi=min(mi,arr[i]);
    }
    int bid=0;
    for(int i=0;i<n;i++){
        bid=where(arr[i], n, mi, mx);
        mins[bid]=st[bid]?min(mins[bid], arr[i]):arr[i];
        maxs[bid]=st[bid]?max(maxs[bid], arr[i]):arr[i];
        st[bid]=true;
    }
    int res=0;
    int lmx=maxs[0];
    int i=1;
    for(;i<=n;i++){
        if(st[i]){
            res=max(res,mins[i]-lmx);
            lmx=maxs[i];
        }
    }
    return res;
}
int main(void){
    vector<int>arr;
    int k;
    while(cin>>k)arr.push_back(k);
    int n=arr.size();
    maxs=vector<int>(n+1);
    mins=vector<int>(n+1);
    st=vector<bool>(n+1,false);
    cout<<vmax(arr,n)<<endl;
}