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https://leetcode.com/problems/first-bad-version/#/description

 

You are a product manager and currently leading a team to develop a new product. Unfortunately, the latest version of your product fails the quality check. Since each version is developed based on the previous version, all the versions after a bad version are also bad.

Suppose you have n versions [1, 2, ..., n] and you want to find out the first bad one, which causes all the following ones to be bad.

You are given an API bool isBadVersion(version) which will return whether version is bad. Implement a function to find the first bad version. You should minimize the number of calls to the API.

 

Sol 1:

Binary search

 

class Solution(object):
    def firstBadVersion(self, n):
        """
        :type n: int
        :rtype: int
        """
        
        
        if isBadVersion(1):
            return 1
        l = 1
        r = n
        while l < r - 1:
            mid = (l+r)/2
            if isBadVersion(mid):
                r = mid
            else:
                l = mid
        return r

 

Sol 2:

Recursion

 

class Solution(object):
    def rec(self,l,r):
        if(l>r):
            return 0
        else:
            mid=(l+r)/2
            if(isBadVersion(mid)):
                if(l==r):
                    return l
                else:
                    return self.rec(l,mid)
            else:
                return self.rec(mid+1,r)
            
    def firstBadVersion(self, n):
        """
        :type n: int
        :rtype: int
        """
        ans=self.rec(1,n)
        return ans

 

 

 

posted on 2017-05-24 19:49  Premiumlab  阅读(107)  评论(0编辑  收藏  举报