C#中通过位运算实现多个状态的判断

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading.Tasks;

namespace StateMachine
{
    class Program
    {
        static void Main(string[] args)
        {
            //输出十进制 - 二进制的值
            Console.WriteLine(State.A + " - " + Program.TwoNum(Convert.ToString(State.A, 2)));
            Console.WriteLine(State.B + " - " + Program.TwoNum(Convert.ToString(State.B, 2)));
            Console.WriteLine(State.C + " - " + Program.TwoNum(Convert.ToString(State.C, 2)));

            //创建一个变量,添加三个状态
            short mark = 0;
            mark |= State.A;
            mark |= State.B;
            mark |= State.C;

            Console.WriteLine("\n");
            Console.WriteLine("mark的值: " + mark + " - " + Program.TwoNum(Convert.ToString(mark, 2)));
            Console.WriteLine("\n状态显示");
            
            //判断一个值里面一共有几个状态
            if ((mark & State.A) > 0)
                Console.WriteLine("拥有A的状态");
            if ((mark & State.B) > 0)
                Console.WriteLine("拥有B的状态");
            if ((mark & State.C) > 0)
                Console.WriteLine("拥有C的状态");
            if ((mark & State.D) > 0)
                Console.WriteLine("拥有D的状态");
            
            Console.ReadLine();
        }

        //默认在后面补上7个0
        public static string TwoNum(string s)
        {
            string temp = "";
            for (int i = s.Length; i < 8; i++)
            {
                temp += "0";
            }

            s = s.Insert(0, temp);
            return s;
        }
    }

    /// <summary>
    /// 状态
    /// </summary>
    public class State
    {
        public static short A = 1 << 0;
        public static short B = 1 << 1;
        public static short C = 1 << 2;
        public static short D = 1 << 3;
        public static short E = 1 << 4;
    }

}