Springboot项目的main函数入口,如何像jar包一样接受参数

一般来说,springboot项目是提供服务的,但是也可以用到导出jar来启动,那么如何介绍参数呢:

package com.example.TestDemo;

import com.example.jmeter.bean.TestCaseResult;
import com.example.jmeter.controller.JmeterController;
import lombok.extern.slf4j.Slf4j;
import org.springframework.beans.BeansException;
import org.springframework.boot.SpringApplication;
import org.springframework.boot.autoconfigure.SpringBootApplication;
import org.springframework.context.ApplicationContext;
import org.springframework.context.ApplicationContextAware;

@SpringBootApplication
@Slf4j
public class JmeterApplication implements ApplicationContextAware {

    private static ApplicationContext applicationContext;

    public static void main(String[] args) {
        SpringApplication.run(JmeterApplication.class, args);
        JmeterController con=(JmeterController) applicationContext.getBean(JmeterController.class);//获取bean实例
        String par=args[0];
        switch (par){
            case "test1":  con.testOneMethod(); break;
            case "test1":  con.testTwoMethod();break;
            case  "test3": con.testThreeMethod(); break;
            default:
                TestCaseResult testCaseResult=new TestCaseResult();
                testCaseResult.setRunBatch(par);
                con.keeperJmeterRetry(testCaseResult,args[1]);


        }
    }

    @Override
    public void setApplicationContext(ApplicationContext applicationContext) throws BeansException {
        JmeterApplication.applicationContext=applicationContext;

    }
}

 

posted @ 2024-03-26 11:36  苹果芒  阅读(122)  评论(0)    收藏  举报