HDU_2055——刷题不要使用fflush()

Problem Description
we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, ... f(Z) = 26, f(z) = -26; Give you a letter x and a number y , you should output the result of y+f(x).
 

 

Input
On the first line, contains a number T.then T lines follow, each line is a case.each case contains a letter and a number.
 

 

Output
for each case, you should the result of y+f(x) on a line.
 

 

Sample Input
6 R 1 P 2 G 3 r 1 p 2 g 3
 

 

Sample Output
19 18 10 -17 -14 -4
 1 #include <cstdio>
 2 int main()
 3 {
 4     int T, n;
 5     char ch;
 6     scanf("%d",&T);
 7     while(T--)
 8         {
 9             //fflush(stdin);//切记不能使用这个.. 
10             getchar();
11             scanf("%c %d",&ch,&n);
12             if(ch>='a'&&ch<='z')
13                 {
14                     printf("%d\n",n+(96-ch));
15                 }
16             else
17                 {
18                     printf("%d\n",n+(ch-64));
19                 }
20         }
21     return 0;    
22 }

 

posted @ 2013-07-11 22:26  瓶哥  Views(322)  Comments(0Edit  收藏  举报