task2--2

#include<stdio.h>
#include<math.h>
int main()
{
    double x, ans;
    while (scanf("%lf", &x) != 0)
    {
        ans = pow(x, 365);
        printf("%.2f的365次方：%.2f\n", x, ans);
        printf("\n");

    }
    return 0;
}