Minimum Path Sum
Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which minimizes the sum of all numbers along its path.
Note: You can only move either down or right at any point in time.
简单的动态规划题。刚开始又写成路径和了……
class Solution {
public:
int minPathSum(vector<vector<int> > &grid) {
vector<int> p(grid.size(),0);
p[0] = grid[0][0];
for(int i = 1; i < grid.size();i++)
p[i] = p[i-1] + grid[i][0];
for(int i =1; i < grid[0].size();i++)
{
p[0] = p[0]+grid[0][i];
for(int j = 1 ; j < grid.size();j++)
{
p[j] = min(p[j],p[j-1]) + grid[j][i];
}
}
return p[grid.size()-1];
}
};
posted on 2014-03-12 10:48 pengyu2003 阅读(173) 评论(0) 收藏 举报
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