Sum Root to Leaf Numbers

Given a binary tree containing digits from 0-9 only, each root-to-leaf path could represent a number.

An example is the root-to-leaf path 1->2->3 which represents the number 123.

Find the total sum of all root-to-leaf numbers.

For example,

    1
   / \
  2   3

 

The root-to-leaf path 1->2 represents the number 12.
The root-to-leaf path 1->3 represents the number 13.

Return the sum = 12 + 13 = 25.

很简单的题……

/**
 * Definition for binary tree
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution {
public:
    int sum = 0;
    int sumNumbers(TreeNode *root) {
        if(root == NULL)return 0;
        bi(root,0);
        return sum;
    }
    void bi(TreeNode *root ,int num)
    {
        num*=10;
        num+=root->val;
        if(root->left  == NULL && root->right == NULL)
        {
            sum += num;
            return;
        }
        if(root->left  != NULL) bi(root->left,num);

        if(root->right  != NULL)bi(root->right,num);
        
    }
};