摘要: 二分查找 # _*_coding:utf-8_*_ def list_number(in_list, number): s_number = 0 d_number = len(in_list) - 1 if number in in_list: while True: mid = (d_number 阅读全文
posted @ 2019-06-27 14:59 Peng_ing 阅读(144) 评论(0) 推荐(0)