hdu 5104 Primes Problem (素数+递推）

Problem Description

Given a number n, please count how many tuple(p1, p2, p3) satisfied that p1<=p2<=p3, p1,p2,p3 are primes and p1 + p2 + p3 = n.

Input

Multiple test cases(less than 100), for each test case, the only line indicates the positive integer

Output

For each test case, print the number of ways.

Sample Input

3

9

Sample Output

0

2

先找出所有素数，再递推。

 1 #include<cstdio>
 2 #include<cstring>
 3 using namespace std;
 4 const int N=10005;
 5 int zj[N],ssb[N],pn,ans,n;
 6 void f()
 7 {
 8     int i,j;
 9     zj[0]=zj[1]=1;
10     pn=0;
11     for (i=2;i<N;i++)
12     {
13         if (!zj[i]) ssb[pn++]=i;
14         for (j=0;j<pn;j++)
15         {
16             if (i*ssb[j]>N) break;
17             zj[i*ssb[j]]=1;
18             if (i%ssb[j]==0) break;
19         }
20     }
21 }
22 void dfs(int sum,int x,int p)
23 {
24     if (p==2)
25     {
26         if (zj[n-sum]==0&&n-sum>=ssb[x]) ans++;
27         return ;
28     }
29     int i;
30     for (i=x;i<pn;i++)
31     {
32         if (sum+ssb[i]>=n) return ;
33         dfs(sum+ssb[i],i,p+1);
34     }
35 }
36 int main()
37 {
38     f();
39     while (~scanf("%d",&n))
40     {
41         ans=0;
42         dfs(0,0,0);
43         printf("%d\n",ans);
44     }
45 }

posted on 2015-08-25 18:52 pb2016 阅读(206) 评论(0) 编辑收藏举报