第六周作业
上机练习:
1.使用for循环计算1-100的和,除了以3结尾的那些数
public class Text1 {
/**
* @param args
*/
public static void main(String[] args) {
// TODO Auto-generated method stub
int sum = 0;
for (int i = 1; i <= 100; i++) {
if (i % 10 != 3 && i != 3)
sum += i;
}
System.out.println("sum=" + sum);
}
}

2.使用二重循环输出以下图形
*
***
*****
*******
*****
****
***
**
*
public static void main(String[] args) { // TODO Auto-generated method stub for (int i = 1; i <= 4; i++) { for (int j = 1; j <= 4 - i; j++) { System.out.print(" "); } for (int m = 1; m <= i * 2 - 1; m++) { System.out.print("*"); } System.out.println("\n"); } System.out.println("\n"); } }

public static void main(String[] args) {
// TODO Auto-generated method stub
for (int i = 1; i <= 5; i++) {
for (int j = 1; j <= 6 - i; j++) {
System.out.print("*");
}
System.out.println("\n");
}
System.out.println("\n");
}
}

3.循环输入学生姓名,直到输入‘Q’程序结束。
public static void main(String[] args) { // TODO Auto-generated method stub Scanner input=new Scanner(System.in); while(true) { System.out.println("输入学生姓名"); String name=input.next(); if(name.equals("Q")) { System.out.println("程序结束"); break; } System.out.println("重新"); } } }

4.输入5个学生成绩,求和,当输入不合法的时候,提示输入错误重新输入。
public static void main(String[] args) { // TODO Auto-generated method stub Scanner input = new Scanner(System.in); double sum = 0; System.out.println("请输入5个学生的成绩:"); for (int i = 1; i <= 5; i++) { System.out.println("请输入第" + i + "个学生的成绩:"); double a = input.nextDouble(); if (a > 100 || a < 0) { System.out.println("提示:输入错误重新输入!"); break; } sum += a; } System.out.println("输入5个学生的成绩和为" + sum); } }

5.计算 1+1/(1+2) + 1/(1+2+3) +1/(1+2+3+4)+…………+1/(1+2+....+10)
public static void main(String[] args) { // TODO Auto-generated method stub double a = 1;// 分字 double b = 0;// 分母 double sum = 0; for (int i = 1; i <= 10; i++) { b = b + i; sum = sum + a / b; } System.out.println(sum); } }

作业
1.产生一个1-99的随机数,猜数字,若大了就提示“大了点”,若小了就提示“小了点”直到猜对为止。
(判断猜的次数,如果1-3次,提示太棒了 如果5-8次 一般般 如果8次以上 太笨了)
public static void main(String[] args) { // TODO Auto-generated method stub Scanner input = new Scanner(System.in); Random a = new Random(); int b = a.nextInt(99); int i = 1; System.out.println("请猜一个数字(1~99):"); for (i = 1; i <= 99; i++) { int num = input.nextInt(); if (num > b) { System.out.println("大了点"); continue; } if (num < b) { System.out.println("小了点"); continue; } if (num == b) { System.out.println("猜对了"); break; } } } }

2.输入一个数,判断是不是质数(只能被1和自身整除的数是质数)
public static void main(String[] args) { // TODO Auto-generated method stub Scanner input = new Scanner(System.in); System.out.println("请输入一个数(该数大于1):"); int num = input.nextInt(); for (int i = 2; i <= num; i++) { if (num % i == 0 && num != i) { System.out.println(num + "不为质数,能被" + i + "整除"); break; } else { System.out.println(num + "为质数!"); break; } } } }

3.求裴波那契数列的第20项是什么。裴波那契数列,1,1,2,3,5,8,13,21……
public static void main(String[] args) { // TODO Auto-generated method stub int a = 1, b = 1, c = 0; for (int i = 1; i <= 18; i++) { c = a + b; a = b; b = c; } System.out.println("裴波那契数列的第20项是:" + c); } }


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