第5次实验
一, 二分法查找
1.1
#include <stdio.h> const int N = 5; int binarySearch(int x[], int n, int item); int main() { int a[N] = { 1,3,9,16,21 }; int i, index, key; printf("数组a中的数据:\n"); for (i = 0; i < N; i++) printf("%d ", a[i]); printf("\n"); printf("输入待查找的数据项: "); scanf_s("%d", &key); index = binarySearch(a, N, key); if (index >= 0) printf("%d在数组中,下标为%d\n", key, index); else printf("%d不在数组中\n", key); return 0; } int binarySearch(int x[], int n, int item) { int low, high, mid; low = 0; high = n - 1; while (low <= high) { mid = (low + high) / 2; if (item == x[mid]) return mid; else if (item < x[mid]) high = mid - 1; else low = mid + 1; } return -1; }
1.2
#include <stdio.h> const int N=5; int binarySearch(int *x, int n, int item); int main() { int a[N]={1,3,9,16,21}; int i,index, key; printf("数组a中的数据:\n"); for(i=0;i<N;i++) printf("%d ",a[i]); printf("\n"); printf("输入待查找的数据项: "); scanf_s("%d", &key); index=binarySearch(a,N,key); if(index>=0) printf("%d在数组中,下标为%d\n", key, index); else printf("%d不在数组中\n", key); return 0; } int binarySearch(int *x, int n, int item) { int low, high, mid; low = 0; high = n-1; while(low <= high) { mid = (low+high)/2; if (item == *(x+mid)) return mid; else if(item<*(x+mid)) high = mid - 1; else low = mid + 1; } return -1; }
二,选择法排序
#include <stdio.h> #include <string.h> void selectSort(char str[][20], int n); // 函数声明,形参str是二维数组名 int main() { char name[][20] = { "John", "Alex", "Joseph", "Candy", "Geoge" }; int i; printf("输出初始名单:\n"); for (i = 0; i < 5; i++) printf("%s\n", name[i]); selectSort(name, 5); // 调用选择法对name数组中的字符串排序 printf("按字典序输出名单:\n"); for (i = 0; i < 5; i++) printf("%s\n", name[i]); return 0; } // 函数定义 // 函数功能描述:使用选择法对二维数组str中的n个字符串按字典序排序 void selectSort(char str[][20], int n) { // 补足代码 int i, j, k; char temp[20]; for (i = 0; i < n - 1; i++) { k = i; strcpy_s(temp, str[i]); for (j = i + 1; j < n; j++) if (strcmp(str[j], str[k]) < 0) k=j; strcpy_s(temp, str[j]); if (k != i) { strcpy_s(temp, str[i]); strcpy_s(str[i], str[k]); strcpy_s(str[k], temp); } } }

独立的 不借助书本和同学的帮助完成一个实验还是有困难 需要多加练习
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