Golang协程并发(并行)的资源竞争问题(2.使用channel)

引出channel

channel的基本介绍

channel的基本使用

注意事项

1.具体代码(不关闭channel)

package main

import (
	"fmt"
)

type Fact struct{
	Num int // n
	Factorial int // n的阶乘
}

func caltulateFactorial(myChan chan Fact, n int){
	res := 1
	for i:=1;i<=n;i++{
		res *= i
	}
	var f Fact = Fact{n, res}
	myChan<- f
}

func main(){
	var myChan = make(chan Fact, 20)
	var f Fact = Fact{}
	
	// 开启20个协程
	for i:=1;i<=20;i++{
		go caltulateFactorial(myChan, i)
	}

	// 输出结果
	for i:=1;i<=20;i++{
		f = <-myChan
		fmt.Println(f.Num,"的阶乘 =", f.Factorial)
	}
}

2.具体代码(关闭channel)

package main


import (
	"fmt"
)

type Fact struct{
	Num int // n
	Factorial int // n的阶乘
}

func caltulateFactorial(myChan chan Fact, boolChan chan bool, n int){
	res := 1
	for i:=1;i<=n;i++{
		res *= i
	}
	var f Fact = Fact{n, res}
	myChan<- f
	boolChan<- true
}

func main(){
	var myChan = make(chan Fact, 20)
	var boolChan = make(chan bool, 20)
	// 开启20个协程
	for i:=1;i<=20;i++{
		go caltulateFactorial(myChan, boolChan, i)
	}

	go func(){
		for i:=0;i<20;i++{
			<-boolChan // 每次取一个,都取出则说明20个协程都执行完毕
		}
		close(myChan)// 此时关闭myChan
	}()	
	
	// 输出结果
	// 因为已经关闭了channel,所以可以用for-range来遍历,否则会报错
	for val := range myChan{
		fmt.Println(val.Num,"的阶乘 =", val.Factorial)
	}
}

结果

posted @ 2021-02-15 15:13  pangqianjin  阅读(300)  评论(3编辑  收藏  举报