BZOJ - 2733: [HNOI2012]永无乡

传送门

对每个联通块建一棵线段树,并用并查集维护联通块的根。

先开始WA了几次,要注意每次操作都是对联通块的根进行的。

 1 #include<cstdio>
 2 #include<iostream>
 3 using namespace std;
 4 inline char nc() {
 5     static char b[1<<14],*s=b,*t=b;
 6     return s==t&&(t=(s=b)+fread(b,1,1<<14,stdin),s==t)?-1:*s++;
 7 }
 8 inline void read(int &x) {
 9     char b = nc(); x = 0;
10     for (; !isdigit(b); b = nc());
11     for (; isdigit(b); b = nc()) x = x * 10 + b - '0';
12 }
13 inline void read(char &x) {
14     for (x = nc(); x != 'B' && x != 'Q'; x = nc());    
15 }
16 const int N = 100010;
17 int rt[N], ls[N*18], rs[N*18], A, r[N], s[N*18];
18 int n, m, fa[N];
19 #define lson l, m, ls[rt]
20 #define rson m + 1, r, rs[rt]
21 int find(int x) {
22     return x == fa[x] ? x : fa[x] = find(fa[x]);
23 }
24 inline void upd(int rt) {
25     s[rt] = s[ls[rt]] + s[rs[rt]];
26 }
27 void add(int p, int l, int r, int &rt) {
28     if (!rt) rt = ++A;
29     if (l == r) return ++s[rt], void();
30     int m = (l + r) >> 1;
31     if (p <= m) add(p, lson);
32     else add(p, rson);
33     upd(rt);
34 }
35 int merge(int x, int y) {
36     if (!x) return y;
37     if (!y) return x;
38     ls[x] = merge(ls[x], ls[y]);
39     rs[x] = merge(rs[x], rs[y]);
40     s[x] += s[y];
41     return x;
42 }
43 int query(int k, int l, int r, int rt) {
44     if (l == r) return l;
45     int m = (l + r) >> 1;
46     if (k <= s[ls[rt]]) return query(k, lson);
47     else return query(k - s[ls[rt]], rson);
48 }
49 int query(int x, int k) {
50     if (s[rt[x]] < k) return -1;
51     return r[query(k, 1, n, rt[x])];
52 }
53 int main() {
54     read(n); read(m);
55     for (int i = 1; i <= n; ++i) fa[i] = i;
56     for (int t, i = 1; i <= n; ++i)
57         read(t), r[t] = i, add(t, 1, n, rt[i]);
58     for (int x, y, i = 0; i < m; ++i) {
59         read(x), read(y);
60         if ((x=find(x)) != (y=find(y))) 
61             rt[y] = merge(rt[x], rt[y]), fa[x] = y;
62     }
63     read(m); char op;
64     for (int i = 0, a, b; i < m; ++i) {
65         read(op); read(a); read(b);
66         if (op == 'B') {if ((a=find(a)) != (b=find(b))) rt[b] = merge(rt[a], rt[b]), fa[a] = b;}
67         else printf("%d\n", query(find(a), b));
68     }
69     return 0;
70 }

 

posted @ 2017-12-26 14:38  p0ny  阅读(122)  评论(0编辑  收藏  举报