好好学习，天天向上

每一天都学习，每一天都会进步，假设你每一天进步0.001，一年之后的你

365*1.001

for i in range(365):

   base = base * (1+0.001)

print(base)

print (pow(1.001,365))
##1.44

如果每天退步一点点

360*0.999

print (pow(0.999,365))
##0.025

周一到周五进步0.01，然后双休日退步0.01，怎么计算

dayup=0.01
daydown=-0.01
for i in range(365//7):  
for i in range(5):      
a = a * (1 + dayup)  
for i in range(2):      
a = a * (1 + daydown)
print(a)

周一到周五努力到什么程度才能 == 每天进步0.01结果一样

factory = 0.01for i in range(10000000):
base = 1
for i in range(365):  # i=1周一  
if i % 7 == 6:   
base *= (1 - 0.01)   
elif i % 7 == 0:    
base *= (1 - 0.01)     
else:         
base *= (1 + factory) 
if base > pow(1.01,365):  
print(factory)  
break 
factory+=0.001
## factory = 1.9  所以平时要努力进步1.9才能够补回来