蜜蜂寻路

题目：https://www.nowcoder.com/pat/2/problem/257

 1 #include <iostream>
 2 #include <stdio.h>
 3 
 4 using namespace std;
 5 
 6 long long diff[103] = { 1, 1, 2 };
 7 //斐波那契数到103项就会超过2^64
 8 
 9 int main()
10 {
11     for (int i = 3; i<103; i++) {
12         diff[i] = diff[i - 1] + diff[i - 2];
13     }
14     unsigned int n; unsigned int a, b, d;
15     scanf("%d", &n);
16     while (n--) {
17         scanf("%d %d", &a, &b); d = b - a;
18         printf("%lld\n", diff[d]);
19     }
20     return 0;
21 }

 

posted @ 2018-01-12 22:21  ouyang_wsgwz  阅读(167)  评论(0)  编辑  收藏  举报