[LeetCode] Contains Duplicate II

Given an array of integers and an integer k, find out whether there are two distinct indices i and j in the array such that nums[i] = nums[j] and the difference between i and j is at most k.

     这道题还是很简单的。没啥可说的。直接用hashmap就可以做了,借助containsKey(),get()还有put()。

     代码如下。~

public class Solution {
    public boolean containsNearbyDuplicate(int[] nums, int k) {
    Map<Integer,Integer>test=new HashMap<>();
    for(int i=0;i<nums.length;i++){
        if(test.containsKey(nums[i])){
            int diff=i-test.get(nums[i]);
            if(diff<=k){
                return true;
            }
        }
        test.put(nums[i],i);
    }
    return false;
        
    }
}

 

posted @ 2015-08-18 09:29  李小橘er  阅读(164)  评论(0)    收藏  举报