和小M的作物类似建图跑最小割即可(这题的建图实在令人郁闷。。

 1 #include<bits/stdc++.h>
 2 #define inc(i,l,r) for(int i=l;i<=r;i++)
 3 #define dec(i,l,r) for(int i=l;i>=r;i--)
 4 #define link(x) for(edge *j=h[x];j;j=j->next)
 5 #define mem(a) memset(a,0,sizeof(a))
 6 #define inf 1e9
 7 #define ll long long
 8 #define succ(x) (1<<x)
 9 #define NM 70000+5
10 #define nm 500000
11 using namespace std;
12 int read(){
13     int x=0,f=1;char ch=getchar();
14     while(!isdigit(ch)){if(ch=='-')f=-1;ch=getchar();}
15     while(isdigit(ch))x=x*10+ch-'0',ch=getchar();
16     return x*f;
17 }
18 struct edge{
19     int t,v;
20     edge *next,*rev;
21 }e[nm],*h[NM],*o=e,*p[NM],*tmp[NM];
22 int ans;
23 void _add(int x,int y,int v){
24     o->v=v;o->t=y;o->next=h[x];h[x]=o;o++;
25 }
26 void add(int x,int y,int v){
27     _add(x,y,v);_add(y,x,0);
28     h[x]->rev=h[y];h[y]->rev=h[x];
29     if(v<inf)ans+=v;
30 }
31 int n,m,v,tot,b[105][105],d[NM],cnt[NM];
32 int maxflow(){
33     int flow=0;edge *j;
34     inc(i,1,n)tmp[i]=h[i];
35     cnt[0]=v;
36     for(int x=0,s=inf;d[x]<v;){
37         for(j=tmp[x];j;j=j->next)
38         if(j->v&&d[j->t]+1==d[x])break;
39         if(j){
40             s=min(s,j->v);tmp[x]=p[j->t]=j;
41             if((x=j->t)==n){
42                 for(;x;x=p[x]->rev->t){
43                     p[x]->v-=s;
44                     p[x]->rev->v+=s;
45                 }
46                 flow+=s;s=inf;
47             }
48         }else{
49             if(!--cnt[d[x]])break;
50             d[x]=v;
51             link(x)
52             if(j->v&&d[j->t]+1<d[x]){
53                 d[x]=d[j->t]+1;
54                 tmp[x]=j;
55             }
56             cnt[d[x]]++;
57             if(x)x=p[x]->rev->t;
58         }
59     }
60     return flow;
61 }
62 int main(){
63 //    freopen("data.in","r",stdin);
64     n=read();m=read();
65     inc(i,1,n)
66     inc(j,1,m)b[i][j]=++tot;
67     v=++tot;
68     inc(i,1,n)
69     inc(j,1,m)add(0,b[i][j],read());
70     inc(i,1,n)
71     inc(j,1,m)add(b[i][j],tot,read());
72     inc(i,1,n-1)
73     inc(j,1,m){
74         v++;
75         add(0,v,read());
76         add(v,b[i][j],inf);add(v,b[i+1][j],inf);
77     }
78     inc(i,1,n-1)
79     inc(j,1,m){
80         v++;
81         add(v,tot,read());
82         add(b[i][j],v,inf);add(b[i+1][j],v,inf);
83     }
84     inc(i,1,n)
85     inc(j,1,m-1){
86         v++;
87         add(0,v,read());
88         add(v,b[i][j],inf);add(v,b[i][j+1],inf);
89     }
90     inc(i,1,n)
91     inc(j,1,m-1){
92         v++;
93         add(v,tot,read());
94         add(b[i][j],v,inf);add(b[i][j+1],v,inf);
95     }
96     n=tot;v++;
97     printf("%d\n",ans-maxflow());
98 }
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posted on 2016-01-03 00:18  onlyRP  阅读(159)  评论(0编辑  收藏  举报