炒鸡简单的高斯乱搞

#include <cstdio>//AC
#include <iostream>
#include <cmath>
using namespace std;
int n;
struct fangcheng
{
    double a[105],b;
    fangcheng operator*(double b)
    {
        fangcheng ans(*this);
        for(int i=1;i<=n;i++)
            ans.a[i]*=b;
        ans.b*=b;
        return ans;
    }
    fangcheng operator/(double b)
    {
        fangcheng ans(*this);
        for(int i=1;i<=n;i++)
            ans.a[i]/=b;
        ans.b/=b;
        return ans;
    }
    fangcheng operator-(fangcheng b)
    {
        fangcheng ans(*this);
        for(int i=1;i<=n;i++)
            ans.a[i]-=b.a[i];
        ans.b-=b.b;
        return ans;
    }
}a[105];
int main()
{
    scanf("%d",&n);
    for(int i=1;i<=n;i++)
    {
        for(int j=1;j<=n;j++)
            scanf("%lf",&a[i].a[j]);
        scanf("%lf",&a[i].b);
    }
    for(int i=1;i<=n;i++)
    {
        if(a[i].a[i]==0){printf("No Solution\n");return 0;}
        a[i]=a[i]/a[i].a[i];
        for(int j=1;j<=n;j++)
        {
            
            if(j==i)continue;
            else a[j]=a[j]-a[i]*a[j].a[i];
        }
    }
    for(int i=1;i<=n;i++)
        printf("%.2lf\n",a[i].b);
}

 

posted @ 2018-01-04 11:54  ghj1222  阅读(157)  评论(0编辑  收藏  举报