Experiment4
#include <stdio.h> #define N 4 int main() { int a[N] = {2, 0, 2, 3}; char b[N] = {'2', '0', '2', '3'}; int i; printf("sizeof(int) = %d\n", sizeof(int)); printf("sizeof(char) = %d\n", sizeof(char));
#include <stdio.h> #define N 5 // 函数声明 void input(int x[], int n); void output(int x[], int n); double average(int x[], int n); void bubble_sort(int x[], int n); int main() { int scores[N]; double ave; printf("录入%d个分数:\n", N); input(scores, N); printf("\n输出课程分数: \n"); output(scores, N); printf("\n课程分数处理: 计算均分、排序...\n"); ave = average(scores, N); bubble_sort(scores, N); printf("\n输出课程均分: %.2f\n", ave); printf("\n输出课程分数(高->低):\n"); output(scores, N); return 0; } // 函数定义 // 输入n个整数保存到整型数组x中 void input(int x[], int n) { int i; for(i = 0; i < n; ++i) scanf("%d", &x[i]); } // 输出整型数组x中n个元素 void output(int x[], int n) { int i; for(i = 0; i < n; ++i) printf("%d ", x[i]); printf("\n"); } // 计算整型数组x中n个元素均值,并返回 // 补足函数average()实现 double average(int x[],int n){ int i; double s=0,a; for(i=0;i<n;i++) s = s+x[i]; a = s/n;
#include <stdio.h> #define N 100 void dec2n(int x, int n); // 函数声明 int main() { int x; printf("输入一个十进制整数: "); while(scanf("%d", &x) != EOF) { dec2n(x, 2); // 函数调用: 把x转换成二进制输出 dec2n(x, 8); // 函数调用: 把x转换成八进制输出 dec2n(x, 16); // 函数调用: 把x转换成十六进制输出 printf("\n输入一个十进制整数: "); } return 0; } void dec2n(int x, int n){ char s[N]="0123456789ABCDEF"; int a[N],j,i=0; char q[N]; while(x!=0){
#include<stdio.h> #define N 100 #define M 4 void output(int x[][N],int n); void rotate_to_right(int x[][N],int n); int main(){ int t[][N]={{21,12,13,24}, {25,16,47,38}, {29,11,32,54}, {42,21,33,10}}; printf("原始矩阵:\n"); output(t,M); rotate_to_right(t,M); printf("变换后矩阵:\n"); output(t,M); system("pause"); return 0; } void output(int x[][N],int n){ int i,j;
#include<stdio.h> #include<stdlib.h> #define N 80 void replace(char x[],char old_char,char new_char); int main(){ char text[N]="c programming is difficult or not,it is a question.";
#include<stdio.h> #define N 80 int main(){ char str[N],ch; int i; printf("输入字符串:"); gets(str);
#include<stdio.h> #include<string.h> #define N 5 #define M 20 void bubble_sort(char str[][M],int n); int main(){ char name[][M]={"Bob","Bill","Joseph","Taylor","George"}; int i; printf("输出初始名单:\n"); for(i=0;i<N;i++) printf("%s\n",name[i]); printf("\n排序中。。。\n"); bubble_sort(name,N); printf("\n按字典序输出名单:\n"); for(i=0;i<N;i++) printf("%s\n",name[i]); return 0; } void bubble_sort(char str[][M], int n){ int i,j,k=0; char tmp[M]; for (i=1;i<n;i++){ for (j=n-1;j>=i;j--){ k=0; if(str[j][k]==str[j-1][k]){ while( str[j][k]==str[j-1][k] && str[j][k]!='\0' && str[j-1][k]!='\0'){ k++;} } if (str[j][k]<str[j-1][k] || str[j][k]=='\0'){ strcpy(tmp, str[j]); strcpy(str[j], str[j-1]); strcpy(str[j-1], tmp); } } } }
printf("输入一个字符:"); ch = getchar(); printf("截断处理:。。。。"); i=0; while(str[i]!='\0'){ if(str[i]==ch) break; i++; } str[i]='\0'; printf("\n截断处理后字符:%s",str); return 0; }
printf("原始文本:\n"); printf("%s\n",text); replace(text,'i','*'); printf("处理后文本:\n"); printf("%s\n",text); system("pause"); return 0; } void replace(char x[],char old_char,char new_char){ int i; for(i=0;x[i]!='\0';++i) if (x[i]==old_char) x[i]=new_char; }
for(i=0;i<n;++i){ for(j=0;j<n;++j) printf("%4d",x[i][j]); printf("\n"); } } void rotate_to_right(int x[][N],int n){ int i,t,j=0; for(i=0;i<n;i++){ t=x[i][n-1]; for(j=n-1;j>=0;j--){ x[i][j]=x[i][j-1]; } x[i][0]=t; } }
a[i]=x%n; x=x/n; i++; } i--; j=0; while (i>=0){ q[j]=s[a[i]]; j++; i--; } q[j]='\0'; printf("%s\n",q); }
return a; } // 对整型数组x中的n个元素降序排序 // 补足函数bubble_sort()实现 void bubble_sort(int x[],int n){ int i,j,t; for(i = 0;i<n;i++){ for(j=0;j<n;j++){ if(x[i]<x[i+1]){ t = x[i]; x[i] = x[i+1]; x[i+1] = t; } } } }
printf("\n"); // 输出int型数组a中每个元素的地址、值 for (i = 0; i < N; ++i) printf("%p: %d\n", &a[i], a[i]); printf("\n"); // 输出char型数组b中每个元素的地址、值 for (i = 0; i < N; ++i) printf("%p: %c\n", &b[i], b[i]); printf("\n"); // 输出数组名a和b对应的值 printf("a = %p\n", a); printf("b = %p\n", b); return 0; }
#include <stdio.h> #define N 2 #define M 3 int main() { int a[N][M] = {{1, 2, 3}, {4, 5, 6}}; char b[N][M] = {{'1', '2', '3'}, {'4', '5', '6'}}; int i, j; // 输出int型二维数组a中每个元素的地址、值 for (i = 0; i < N; ++i) for (j = 0; j < M; ++j) printf("%p: %d\n", &a[i][j], a[i][j]); printf("\n"); // 输出int型二维数组名a, 以及,a[0], a[1]的值 printf("a = %p\n", a); printf("a[0] = %p\n", a[0]); printf("a[1] = %p\n", a[1]); printf("\n"); // 输出char型二维数组b中每个元素的地址、值 for (i = 0; i < N; ++i) for (j = 0; j < M; ++j) printf("%p: %c\n", &b[i][j], b[i][j]); printf("\n"); // 输出char型二维数组名b, 以及,b[0], b[1]的值 printf("b = %p\n", b); printf("b[0] = %p\n", b[0]); printf("b[1] = %p\n", b[1]); printf("\n"); return 0; }
#include <stdio.h> #include <string.h> #define N 80 void swap_str(char s1[N], char s2[N]); void test1(); void test2(); int main(){ printf("测试1: 用两个一维维数组,实现两个字符串交换\n"); test1(); printf("\n测试: 用二维数组,实现两个字符串交换\n"); test2(); return 0; } void test1() { char views1[N] = "hey, C, I hate u."; char views2[N] = "hey, C, I love u."; printf("交换前: \n"); puts(views1); puts(views2); swap_str(views1, views2); printf("交换后: \n"); puts(views1); puts(views2); } void test2() { char views[2][N] = {"hey, C, I hate u.", "hey, C, I love u."}; printf("交换前: \n"); puts(views[0]); puts(views[1]); swap_str(views[0], views[1]); printf("交换后: \n"); puts(views[0]); puts(views[1]); } void swap_str(char s1[N], char s2[N]) { char tmp[N]; strcpy(tmp, s1); strcpy(s1, s2); strcpy(s2, tmp); }
#include <stdio.h> #define N 80 int count(char x[]); int main() { char words[N+1]; int n;
#include<stdio.h> #include<stdlib.h> #define N 1000 int main(){ char line[N]; int word_len; int max_len; int end; int i; while(gets(line)!=NULL){ word_len=0; max_len=0; end=0; i=0; while(1){ while(line[i]==' '){ word_len=0; i++; } while(line[i]!='\0'&&line[i]!=' '){ word_len++; i++; } if(max_len<word_len){ max_len=word_len; end=i; } if(line[i]=='\0') break; } printf("最长单词:"); for(i=end-max_len;i<end;++i) printf("%c",line[i]); printf("\n\n"); } system("pause"); return 0; }
while(gets(words) != NULL) { n = count(words); printf("单词数: %d\n\n", n); } return 0; } int count(char x[]) { int i; int word_flag = 0; // 用作单词标志,一个新单词开始,值为1;单词结束,值为0 int number = 0; // 统计单词个数 for(i = 0; x[i] != '\0'; i++) { if(x[i] == ' ') word_flag = 0; else if(word_flag == 0) { word_flag = 1; number++; } } return number; }