【树】938. 二叉搜索树的范围和

题目:

 

 

解答:

 

 

 1 /**
 2  * Definition for a binary tree node.
 3  * struct TreeNode {
 4  *     int val;
 5  *     TreeNode *left;
 6  *     TreeNode *right;
 7  *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 8  * };
 9  */
10 class Solution {
11 public:
12     int rangeSumBST(TreeNode* root, int L, int R) 
13     {
14         if (root == NULL) 
15         {
16             return 0;
17         }
18         if (root->val < L) 
19         {
20             return rangeSumBST(root->right, L, R);
21         }
22         if (root->val > R) 
23         {
24             return rangeSumBST(root->left, L, R);
25         }
26         return root->val + rangeSumBST(root->left, L, R) + rangeSumBST(root->right, L, R);
27     }
28 };

 

posted @ 2020-05-03 15:39  梦醒潇湘  阅读(159)  评论(0)    收藏  举报