实验七
任务三:正确生成了符合要求的信息,生成了file3.dat,里面的信息清晰可观。
任务四:正确生成了符合要求的信息,生成了file4.dat,里面的信息不是清晰可观。
`#include <stdio.h>
include <stdlib.h>
define N 20
typedef struct student {
int num;
char name[20];
int score;
}STU;
int main(){
int i;
STU st[N];
FILE *fin;
fin = fopen("file4.dat", "rb");
if(fin == NULL){
printf("cannot open file \n");
exit(0);
}
for(i=0;i<N;i++){
printf("%-6d%-10s%3d\n", st[i].num, st[i].name, st[i].score);
}
fclose(fin);
return 0;
}`
`#include <stdio.h>
include <string.h>
include <stdlib.h>
const int N = 10;
// 定义结构体类型struct student,并定义其别名为STU
typedef struct student {
long int id;
char name[20];
float objective; /客观题得分/
float subjective; /操作题得分/
float sum;
char level[10];
}STU;
// 函数声明
void input(STU s[], int n,FILE *fp);
void output(STU s[], int n,FILE *fout);
void process(STU s[], int n);
int main() {
STU stu[N];
FILE *fp;
FILE *fout;
fp=fopen("examinee.txt","r");
printf("录入%d个考生信息: 准考证号,姓名,客观题得分(<=40),操作题得分(<=60)\n", N);
input(stu, N, fp);
fout=fopen("result.txt","w");
printf("\n对考生信息进行处理: 计算总分,确定等级\n");
process(stu, N);
printf("\n打印考生完整信息: 准考证号,姓名,客观题得分,操作题得分,总分,等级\n");
output(stu, N, fout);
fclose(fp);
fclose(fout);
return 0;
}
// 从文本文件examinee.txt读入考生信息:准考证号,姓名,客观题得分,操作题得分
void input(STU s[], int n,FILE *fp) {
int i;
for(i=0;i<n;i++)
{
fscanf(fp,"%ld %s %f %f",&s[i].id,s[i].name,&s[i].objective,&s[i].subjective);
if(s[i].objective>40&&s[i].subjective>60)
exit(0);
}
}
// 输出考生完整信息: 准考证号,姓名,客观题得分,操作题得分,总分,等级
// 不仅输出到屏幕上,还写到文本文件result.txt中
void output(STU s[], int n,FILE *fout) {
int i;
for(i=0;i<n;i++)
{
printf("%ld,%s,%.2f,%.2f,%.2f,%s",s[i].id,s[i].name,s[i].objective,s[i].subjective,s[i].sum,s[i].level);
printf("\n");
fprintf(fout,"%ld,%s,%.2f,%.2f,%.2f,%s",s[i].id,s[i].name,s[i].objective,s[i].subjective,s[i].sum,s[i].level);
fprintf(fout,"\n");
}
}
// 对考生信息进行处理:计算总分,排序,确定等级
void process(STU s[], int n) {
STU temp;
int i,j;
for(i=0;i<n;i++)
{
s[i].sum=s[i].objective+s[i].subjective;
}
for (i = 0; i < n - 1; i++){
for (j = 0; j < n - 1 - i; j++){
if (s[j].sum < s[j + 1].sum)
{
temp = s[j];
s[j] = s[j + 1];
s[j+1] = temp;
}
}
}
for (i = 0; i < n; i++)
{
if (i <0.1*n)
strcpy(s[i].level, "优秀");
else if (i >= 0.1*n&&i <0.5*n)
strcpy(s[i].level, "合格");
else
strcpy(s[i].level, "不合格");
}
}`