任务4
#include<stdio.h>
#define N 10
typedef struct
{
char isbn[20];
char name[80];
char author[80];
double sales_price;
int sales_count;
}Book;
void output(Book x[],int n);
void sort(Book x[],int n);
double sales_amount(Book x[],int n);
int main()
{
Book x[N]={{"978-7-5327-6082-4", "门将之死", "罗纳德.伦", 42, 51},
{"978-7-308-17047-5", "自由与爱之地：入以色列记", "云也退", 49 , 30},
{"978-7-5404-9344-8", "伦敦人", "克莱格泰勒", 68, 27},
{"978-7-5447-5246-6", "软件体的生命周期", "特德姜", 35, 90},
{"978-7-5722-5475-8", "芯片简史", "汪波", 74.9, 49},
{"978-7-5133-5750-0", "主机战争", "布莱克.J.哈里斯", 128, 42},
{"978-7-2011-4617-1", "世界尽头的咖啡馆", "约翰·史崔勒基", 22.5, 44},
{"978-7-5133-5109-6", "你好外星人", "英国未来出版集团", 118, 42},
{"978-7-1155-0509-5", "无穷的开始:世界进步的本源", "戴维·多伊奇", 37.5, 55},
{"978-7-229-14156-1", "源泉", "安.兰德", 84, 59}};
printf("图书销售排名（按销售册数）：\n");
sort(x,N);
output(x,N);
printf("\n图书销售总额：%.2f\n",sales_amount(x,N));
return 0;
}
void sort(Book x[],int n)
{
int i,j;
Book t;
for(i=0;i<n;i++)
{
for(j=0;j<n-1-i;j++)
{
if(x[j].sales_count<x[j+1].sales_count)
{
t=x[j];
x[j]=x[j+1];
x[j+1]=t;
}
}
}
}
double sales_amount(Book x[],int n)
{
double sum=0;
int i;
for(i=0;i<n;i++)
sum+=x[i].sales_price*x[i].sales_count;
return sum;
}
void output(Book x[],int n)
{
int i;
printf("ISBN号 书名 作者 售价 销售册数\n");
for(i=0;i<n;i++)
printf("%-20s%-27s%-20s%-20g%-20d\n",x[i].isbn,x[i].name,x[i].author,x[i].sales_price,x[i].sales_count);
}
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任务5
#include <stdio.h>
typedef struct {
int year;
int month;
int day;
} Date;
void input(Date *pd);
int day_of_year(Date d);
int compare_dates(Date d1, Date d2);
void test1()
{
Date d;
int i;
printf("输入日期:(以形如2025-12-19这样的形式输入)\n");
for(i = 0; i < 3; ++i)
{
input(&d);
printf("%d-%02d-%02d是这一年中第%d天\n\n", d.year, d.month, d.day, day_of_year(d));
}
}
void test2()
{
Date Alice_birth, Bob_birth;
int i;
int ans;
printf("输入Alice和Bob出生日期:(以形如2025-12-19这样的形式输入)\n");
for(i = 0; i < 3; ++i)
{
input(&Alice_birth);
input(&Bob_birth);
ans = compare_dates(Alice_birth, Bob_birth);
if(ans == 0)
printf("Alice和Bob一样大\n\n");
else if(ans == -1)
printf("Alice比Bob大\n\n");
else
printf("Alice比Bob小\n\n");
}
}
int main()
{
printf("测试1: 输入日期, 打印输出这是一年中第多少天\n");
test1();
printf("\n测试2: 两个人年龄大小关系\n");
test2();
}
void input(Date *pd)
{
scanf("%d-%d-%d",&pd->year,&pd->month,&pd->day);
}
int day_of_year(Date d)
{
int days;
switch(d.month)
{
case 1:days=d.day;break;
case 2:days=31+d.day;break;
case 3:days=59+d.day;break;
case 4:days=90+d.day;break;
case 5:days=120+d.day;break;
case 6:days=151+d.day;break;
case 7:days=181+d.day;break;
case 8:days=212+d.day;break;
case 9:days=243+d.day;break;
case 10:days=273+d.day;break;
case 11:days=304+d.day;break;
case 12:days=334+d.day;break;
default:break;
}
if(d.year%4==0&&d.year%100!=0||d.year%400==0)
if(d.month>2)
days+=1;
return days;
}
int compare_dates(Date d1, Date d2)
{
if(d1.year>d2.year)
return 1;
else if(d1.year<d2.year)
return -1;
else
{
if(d1.month>d2.month)
return 1;
else if(d1.month<d2.month)
return -1;
else
{
if(d1.day>d2.day)
return 1;
else if(d1.day<d2.day)
return -1;
else
return 0;
}
}
}
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任务6
#include <stdio.h>
#include <string.h>
enum Role {admin, student, teacher};
typedef struct
{
char username[20];
char password[20];
enum Role type;
} Account;
void output(Account x[], int n);
int main()
{
Account x[] = {{"A1001", "123456", student},
{"A1002", "123abcdef", student},
{"A1009", "xyz12121", student},
{"X1009", "9213071x", admin},
{"C11553", "129dfg32k", teacher},
{"X3005", "921kfmg917", student}};
int n;
n = sizeof(x)/sizeof(Account);
output(x, n);
return 0;
}
void output(Account x[], int n)
{
int i,j;
for(i=0;i<n;i++)
{
for(j=0;j<strlen(x[i].password);j++)
x[i].password[j]='*';
printf("%-10s%-16s",x[i].username,x[i].password);
switch(x[i].type)
{
case 0:{printf("admin\n");break;}
case 1:{printf("student\n");break;}
case 2:{printf("teacher\n");break;}
default:break;
}
}
}
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任务7
#include <stdio.h>
#include <string.h>
#define N 10
typedef struct
{
char name[20];
char phone[12];
int vip;
} Contact;
void set_vip_contact(Contact x[], int n, char name[]);
void output(Contact x[], int n);
void display(Contact x[], int n);
int main()
{
Contact list[N] = {{"刘一", "15510846604", 0},
{"陈二", "18038747351", 0},
{"张三", "18853253914", 0},
{"李四", "13230584477", 0},
{"王五", "15547571923", 0},
{"赵六", "18856659351", 0},
{"周七", "17705843215", 0},
{"孙八", "15552933732", 0},
{"吴九", "18077702405", 0},
{"郑十", "18820725036", 0}};
int vip_cnt, i;
char name[20];
printf("显示原始通讯录信息: \n");
output(list, N);
printf("\n输入要设置的紧急联系人个数: ");
scanf("%d", &vip_cnt);
printf("输入%d个紧急联系人姓名:\n", vip_cnt);
for(i = 0; i < vip_cnt; ++i)
{
scanf("%s", name);
set_vip_contact(list, N, name);
}
printf("\n显示通讯录列表:(按姓名字典序升序排列,紧急联系人最先显示)\n");
display(list, N);
return 0;
}
void set_vip_contact(Contact x[], int n, char name[])
{
int i;
for(i=0;i<n;i++)
{
if(strcmp(x[i].name,name)==0)
x[i].vip=1;
}
}
void display(Contact x[], int n)
{
int i,j;
Contact t;
for(i=0;i<n;i++)
for(j=i+1;j<n;j++)
if(strcmp(x[i].name,x[j].name)>0)
{
t=x[i];
x[i]=x[j];
x[j]=t;
}
for(i=0;i<n;i++)
{
if(x[i].vip==1)
{
printf("%-10s%-15s", x[i].name, x[i].phone);
printf("*\n");
}
}
for(i=0;i<n;i++)
{
if(x[i].vip==0)
printf("%-10s%-15s\n", x[i].name, x[i].phone);
}
}
void output(Contact x[], int n)
{
int i;
for(i = 0; i < n; ++i)
{
printf("%-10s%-15s", x[i].name, x[i].phone);
if(x[i].vip)
printf("%5s", "*");
printf("\n");
}
}
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