实验6

试验任务4

#define _CRT_SECURE_NO_WARNINGS
#include<stdio.h>
#include<string.h>
#define N 10
typedef struct {
    char isbn[20];
    char name[80];
    char author[80];
    double price;
    int count;
}Book;
void output(Book x[], int n) {
    printf("ISBN号\t\t\t\t书名\t\t\t\t作者\t\t\t售价\t销售册数\n");
    for (int i = 0; i < n; i++) {
        printf("%-32s", x[i].isbn);
        printf("%-32s", x[i].name);
        printf("%-25s", x[i].author);
        printf("%g\t%d\n", x[i].price, x[i].count);


    }
}
void sort(Book x[], int n) {
    int t; char m[80]; double a; char h[80]; char k[80];
    for (int i = 0; i < N; i++) {
        for (int j = 0; j <=i; j++) {
            if (x[i].count > x[j].count) {
                t = x[i].count;
                x[i].count = x[j].count;
                x[j].count = t;
                a = x[i].price;
                x[i].price = x[j].price;
                x[j].price = a;
                strcpy(m, x[i].isbn);
                strcpy(x[i].isbn, x[j].isbn);
                strcpy(x[j].isbn,m);
                strcpy(h, x[i].name);
                strcpy(x[i].name, x[j].name);
                strcpy(x[j].name, h);
                strcpy(k, x[i].author);
                strcpy(x[i].author, x[j].author);
                strcpy(x[j].author, k);
               
                
                
            }
        }
    }
}
double amount(Book x[], int n) {
    double m = 0;
    for (int i = 0; i < N; i++)
        m += x[i].price * x[i].count;
    return m;
}
int main() {
    Book x[N] = { {"978-7-5327-6082-4", "门将之死", "罗纳德.伦", 42, 51},
                  {"978-7-308-17047-5", "自由与爱之地：入以色列记", "云也退", 49 , 30},
                  {"978-7-5404-9344-8", "伦敦人", "克莱格泰勒", 68, 27},
                  {"978-7-5447-5246-6", "软件体的生命周期", "特德姜", 35, 90},
                  {"978-7-5722-5475-8", "芯片简史", "汪波", 74.9, 49},
                  {"978-7-5133-5750-0", "主机战争", "布莱克.J.哈里斯", 128, 42},
                  {"978-7-2011-4617-1", "世界尽头的咖啡馆", "约翰·史崔勒基", 22.5, 44},
                  {"978-7-5133-5109-6", "你好外星人", "英国未来出版集团", 118, 42},
                  {"978-7-1155-0509-5", "无穷的开始:世界进步的本源", "戴维·多伊奇", 37.5, 55},
                  {"978-7-229-14156-1", "源泉", "安.兰德", 84, 59} };
    printf("图书销量排名:\n");
    sort(x, N);
    output(x, N);
    printf("\n图书销量总额:%.2f\n", amount(x, N));

    return 0;
}

图片

 

 

 

 

 

试验任务5：

#include<stdio.h>
typedef struct{
    int year;
    int month;
    int day;
}Date;
void input(Date*pd){
    scanf("%d-%d-%d",&pd->year,&pd->month,&pd->day);
}
int dayofyear(Date d){
    int n=0;
    switch(d.month){
        case 1:n=0;break;
        case 2:n=31;break;
        case 3:n=31+28;break;
        case 4:n=31*2+28;break;
        case 5:n=31*2+28+30;break;
        case 6:n=31*3+28+30;break;
        case 7:n=31*3+28+30*2;break;
        case 8:n=31*4+28+30*2;break;
        case 9:n=31*5+28+30*2;break;
        case 10:n=31*5+28+30*3;break;
        case 11:n=31*6+28+30*3;break;
        case 12:n=31*6+28+30*4;break;
    }
    int t=0;
    if(d.year%400==0)
    t=1;
    else if(d.year%4==0&&d.year%100!=0)
    t=1;
    else
    t=0;
    if(t==1&&d.month>2)
    n=n+1+d.day;
    else
    n=n+d.day;
    return n;
}
int compare(Date d1,Date d2){
    if(d1.year>d2.year)
    return 1;
    else if(d1.year<d2.year)
    return -1;
    else{
        if(d1.month<d2.month)
        return -1;
        else if(d1.month>d2.month)
        return 1;
        else{
            if(d1.day<d2.day)
            return -1;
            else if(d1.day>d2.day)
            return 1;
            else return 0;
        }    }
    
}

void test1(){
    Date d;
    int i;
    printf("输入日期\n");
    for(i=0;i<3;i++){
        input(&d);
        printf("%d-%02d-%02d是一年的第%d天\n\n",d.year,d.month,d.day,dayofyear(d));
        
    }
}
void test2(){
    Date Alice,Bob;
    int i;int ans;
    printf("输入Alice和Bob的出生日期\n");
    for(i=0;i<3;i++){
        input(&Alice);
        input(&Bob);
        ans=compare(Alice,Bob);
        if(ans == 0)
            printf("Alice和Bob一样大\n\n");
        else if(ans == -1)
            printf("Alice比Bob大\n\n");
        else
            printf("Alice比Bob小\n\n");
        
    }
}
int main(){
      printf("测试1: 输入日期, 打印输出这是一年中第多少天\n");
    test1();

    printf("\n测试2: 两个人年龄大小关系\n");
    test2();
    
} 

试验任务6：

 

#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
#include <string.h>

enum Role { admin, student, teacher };

typedef struct {
    char username[20];  
    char password[20];  
    enum Role type;     
} Account;



void output(Account x[], int n);    

int main() {
    Account x[] = { {"A1001", "123456", student},
                    {"A1002", "123abcdef", student},
                    {"A1009", "xyz12121", student},
                    {"X1009", "9213071x", admin},
                    {"C11553", "129dfg32k", teacher},
                    {"X3005", "921kfmg917", student} };
    int n;
    n = sizeof(x) / sizeof(Account);
    output(x, n);

    return 0;
}


void output(Account x[], int n) {
    int len;
    for (int i = 0; i < n; i++) {
        len = strlen(x[i].password);
        printf("%-10s", x[i].username);
        for (int j = 0; j < len; j++)
            printf("*");
        printf("\t");
        switch (x[i].type) {
        case admin:printf("admin\n"); break;
        case student:printf("student\n"); break;
        case teacher:printf("teacher\n"); break;

        }
    }
}

 

 

 

 

 

实验任务7：

源代码

#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>
#include <string.h>

typedef struct {
    char name[20];      
    char phone[12];     
    int  vip;           
} Contact;



void set_vip_contact(Contact x[], int n, char name[]); 
void output(Contact x[], int n);    
void display(Contact x[], int n);   


#define N 10
int main() {
    Contact list[N] = { {"刘一", "15510846604", 0},
                       {"陈二", "18038747351", 0},
                       {"张三", "18853253914", 0},
                       {"李四", "13230584477", 0},
                       {"王五", "15547571923", 0},
                       {"赵六", "18856659351", 0},
                       {"周七", "17705843215", 0},
                       {"孙八", "15552933732", 0},
                       {"吴九", "18077702405", 0},
                       {"郑十", "18820725036", 0} };
    int vip_cnt, i;
    char name[20];

    printf("显示原始通讯录信息: \n");
    output(list, N);

    printf("\n输入要设置的紧急联系人个数: ");
    scanf("%d", &vip_cnt);

    printf("输入%d个紧急联系人姓名:\n", vip_cnt);
    for (i = 0; i < vip_cnt; ++i) {
        scanf("%s", name);
        set_vip_contact(list, N, name);
    }

    printf("\n显示通讯录列表:(按姓名字典序升序排列,紧急联系人最先显示)\n");
    display(list, N);

    return 0;
}
void set_vip_contact(Contact x[], int n, char name[]) {
    for (int i = 0; i < n; i++) {
        for (int j = 0; j < N; j++) {
            if (strcmp(name, x[j].name) == 0) {
                x[j].vip = 1;
            }
        }
    }
}

void display(Contact x[], int n) {
    Contact t; int k = 0;
    for (int i = 0; i < n; i++) {
        if (x[i].vip == 1) {
            t = x[k];
            x[k] = x[i];
            x[i] = t;
            k++;
        }
    }
    for (int i = 0; i < k - 1; i++)
        for (int j = 0; j < k - i - 1; j++)
            if (strcmp(x[j].name, x[j + 1].name) > 0) {
                t = x[j];
                x[j] = x[j + 1];
                x[j + 1] = t;
            }

    for (int i = k; i <N; i++) {
        for (int j = k; j <=i; j++) {
            if (strcmp(x[i].name, x[j ].name) < 0) {
                t = x[i];
                x[i] = x[j ];
                x[j ] = t;
            }
        }
    }
    for (int i = 0; i < n; ++i) {
        printf("%-10s%-15s", x[i].name, x[i].phone);
        if (x[i].vip)
            printf("%5s", "*");
        printf("\n");

    }
}

void output(Contact x[], int n) {
    int i;

    for (i = 0; i < n; ++i) {
        printf("%-10s%-15s", x[i].name, x[i].phone);
        if (x[i].vip)
            printf("%5s", "*");
        printf("\n");
    }
}