任务一 不可以因为返回值只能返回一个 而根有两个。
//ex2_1
#include<stdio.h>
int func(int, int);
int main() {
int k=4,m=1,p1,p2;
p1 = func(k,m) ;
p2 = func(k,m) ;
printf("%d,%d\n",p1,p2) ;
return 0;
}
int func(int a,int b) {
static int m=0,i=2;
i += m+1;
m = i+a+b;
return (m);
}
//ex2_2
#include<stdio.h>
int func(int, int);
int main() {
int k=4,m=1,p1,p2;
p1 = func(k,m) ;
p2 = func(k,m) ;
printf("%d,%d\n",p1,p2) ;
return 0;
}
int func(int a,int b) {
static int m=0,i=2;
i += m+1;
m = i+a+b;
return (m);
}
//报告!一致!8 17!qwq
//ex3
#include <stdio.h>
#define N 1000
int fun(int n,int m,int bb[N]) {
int i,j,k=0,flag;
for(j=n;j<=m;j++) {
flag=1;
for(i=2;i<j;i++)
if(j%i==0) {
flag=0;
break;
}
if(flag)
bb[k++]=j;
}
return k;
}
int main(){
int n=0,m=0,i,k,bb[N];
scanf("%d",&n);
scanf("%d",&m);
for(i=0;i<m-n;i++)
bb[i]=0;
k=fun(n,m,bb);
for(i=0;i<k;i++)
printf("%4d",bb[i]);
return 0;
}
//Ex4
#include <stdio.h>
long long fun(int n);
int main() {
int n;
long long f;
while(scanf("%d", &n) != EOF) {
f = fun(n);
printf("n = %d, f = %lld\n", n, f);
}
return 0;
}
long long fun(int n){
int p,m=1;
for(int i=1;i<=n;i++){
m*=2;
}
p=m-1;
return p;
}
//ex5
#include <stdio.h>
void draw(int n, char symbol); // 函数声明
#include <stdio.h>
int main() {
int n, symbol;
while(scanf("%d %c", &n, &symbol) != EOF) {
draw(n, symbol); // 函数调用
printf("\n");
}
return 0;
}
void draw(int n,char symbol){
int line=n-1;
int num=1;
for(int i=0;i<n;i++){
for(int j=0;j<line;j++){
printf(" ");
}
for(int k=0;k<2*num-1;k++){
printf("%c",symbol);
}
printf("\n");
line--;
num++;
}
}
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