274. H-Index && 275. H-Index II
274. H-Index
Given an array of citations (each citation is a non-negative integer) of a researcher, write a function to compute the researcher's h-index.
According to the definition of h-index on Wikipedia: "A scientist has index h if h of his/her N papers have at least h citations each, and the other N − h papers have no more than h citations each."
For example, given citations = [3, 0, 6, 1, 5], which means the researcher has 5 papers in total and each of them had received 3, 0, 6, 1, 5 citations respectively. Since the researcher has 3 papers with at least 3 citations each and the remaining two with no more than 3 citations each, his h-index is 3.
Note: If there are several possible values for h, the maximum one is taken as the h-index.
Hint:
- An easy approach is to sort the array first.
- What are the possible values of h-index?
- A faster approach is to use extra space.
public class Solution { public int hIndex(int[] citations) { Arrays.sort(citations); int l = citations.length -1; int hIndex = 0; for(int i = l; i>=0; --i) { int count = l-i+1; if(citations[i]>=count) hIndex = count; else break; } return hIndex; } }
O(n) Time, O(n) Space
public class Solution { public int hIndex(int[] citations) { int len = citations.length; if (len == 0) return 0; //create a count array such that // index is the citation, value is the count. // all citations > len, go to the end. int[] paperCount = new int[len + 1]; for (int citation : citations) { if (citation > len) paperCount[len] += 1; else paperCount[citation] += 1; } int totalPapers = 0; for (int citation = len; citation >= 0; --citation) { totalPapers += paperCount[citation]; if (totalPapers >= citation) return citation; } return 0; } }
275. H-Index II
Follow up for H-Index: What if the citations array is sorted in ascending order? Could you optimize your algorithm?
Hint:
- Expected runtime complexity is in O(log n) and the input is sorted.
public class Solution { public int hIndex(int[] citations) { int l = citations.length -1; int hIndex = 0; int left = 0; int right = l; while(left<=right){ int mid = (left+right)/2; int numberOfPaper = l+1-mid; //number of papers that have >= citations[mid] citations. if(citations[mid]>=numberOfPaper) { right = mid-1; hIndex = numberOfPaper; } else left = mid+1; } return hIndex; } }

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