windows mobile 实现单实例启动

通过创建互斥量来实现但启动，下面贴部分代码：
        IntPtr hMutex = IntPtr.Zero;
        hMutex = CreateMutex(null, true, "SUPERMAIL-WM");
        int err = Marshal.GetLastWin32Error();
        if(err!=0)
          {
             // 如果已经有程序运行，则立刻退出
               if (err == ERROR_ALREADY_EXISTS)
                {
                    return;
                }
                    // 如果没有，则重试三次
               for(int i=0;i<3;i++)
                {
                    hMutex = CreateMutex(null, true, "SUPERMAIL-WM");
                    err = Marshal.GetLastWin32Error();
                    if (err == ERROR_ALREADY_EXISTS)
                    {
                        return;
                    }
                    System.Threading.Thread.Sleep(1000);
                 }                    
           }

下面是用到的win32 函数，通过P/Invoke调用
        [DllImport("coredll.Dll", SetLastError = true)]
        private static extern int ReleaseMutex(IntPtr hMutex);

        [DllImport("coredll.Dll", SetLastError = true)]
        private static extern IntPtr CreateMutex(SECURITY_ATTRIBUTES lpMutexAttributes, bool bInitialOwner, string lpName);

        [StructLayout(LayoutKind.Sequential)]
        public class SECURITY_ATTRIBUTES
        {
            public int nLength;
            public int lpSecurityDescriptor;
            public int bInheritHandle;
        }
        const int ERROR_ALREADY_EXISTS = 0183;

记得在程序退出的时候要调用ReleaseMutex 来销毁互斥量。