字符串简单加密解密函数（转）
今天在网上找到一个简单的方法，足够用了，转过来备忘。:)
1
public static string DecryptStr( string rs ) //顺序减1解码
2
{
3
byte[] by=new byte[rs.Length];
4for( int i=0;
5i<=rs.Length-1;
6i++ )
7
{
8by[i]=( byte )( ( byte )rs[i]-1 );
9
}
10rs="";
11for( int i=by.Length-1;
12i>=0;
13i-- )
14{
15rs+=( ( char )by[i] ).ToString( );
16}
17return rs;
18
}
19
20public static string EncryptStr( string rs ) //倒序加1加密
21{
22byte[] by=new byte[rs.Length];
23for( int i=0;
24i<=rs.Length-1;
25i++ )
26{
27by[i]=( byte )( ( byte )rs[i]+1 );
28}
29rs="";
30for( int i=by.Length-1;
31i>=0;
32i-- )
33{
34rs+=( ( char )by[i] ).ToString( );
35}
36return rs;
37}
38
39
public static string DecryptStr( string rs ) //顺序减1解码 2
{
3
byte[] by=new byte[rs.Length];4
for( int i=0;5
i<=rs.Length-1;6
i++ )7
{
8
by[i]=( byte )( ( byte )rs[i]-1 );9
}10
rs="";11
for( int i=by.Length-1;12
i>=0;13
i-- )14
{15
rs+=( ( char )by[i] ).ToString( );16
}17
return rs;18
}19
20
public static string EncryptStr( string rs ) //倒序加1加密 21
{22
byte[] by=new byte[rs.Length];23
for( int i=0;24
i<=rs.Length-1;25
i++ )26
{27
by[i]=( byte )( ( byte )rs[i]+1 );28
}29
rs="";30
for( int i=by.Length-1;31
i>=0;32
i-- )33
{34
rs+=( ( char )by[i] ).ToString( );35
}36
return rs;37
}38
39
