归并排序
归并排序的概念和原理我就不介绍了,网上的相关资料一箩筐。在这里,我只想记录一个思路,归并的排序分为三步走:1 分割,2 递归,3 合并。下面我将分别针对数组和链表两种情况的归并排序,写一下程序和思路。关于链表的归并排序,这个题目我在网易有道的面试中经历过。当时蒙住了,因为绝大多数的数据结构的书,以及算法的书介绍归并排序的时候往往都是以数组为例的。
数组归并排序代码:
/***归并排序三步走:1 分割子问题;2 递归;3 合并子问题。*/#include "stdafx.h"#include <iostream>using namespace std;void mergeArray(int *a, int begin1, int length1, int begin2, int length2){int length = length1 + length2;int begin = begin1;int *b = new int[length];int pos = 0;int cur1 = begin1;int cur2 = begin2;while((cur1 - begin1 + 1) <= length1 && (cur2 - begin2 + 1) <= length2){if(a[cur1] <= a[cur2]){b[pos] = a[cur1];cur1++;pos++;}else{b[pos] = a[cur2];cur2++;pos++;}}//前半段的数组已经合并完毕,可以直接将后半段的数组复制到数据bif((cur1 - begin1 + 1) > length1){while((cur2 - begin2 + 1) <= length2){b[pos] = a[cur2];cur2++;pos++;}}else if((cur2 - begin2 + 1) > length2){while((cur1 - begin1 + 1) <= length1){b[pos] = a[cur1];cur1++;pos++;}}//将合并后的数组b复制给数据afor(int i = 0; i < length; i++){a[begin] = b[i];begin++;}}void mergeSort(int *a, int left, int right){if(left >= right)return;int mid = left + (right - left)/2;mergeSort(a, left, mid);mergeSort(a, mid+1, right);int length1 = mid - left + 1;int length2 = right -(mid + 1) + 1;mergeArray(a, left, length1, mid + 1, length2);}int _tmain(int argc, _TCHAR* argv[]){int a[5] = {3, 5, 1, 2, 7};//int a[5] = {1,1,2,1,1};mergeSort(a, 0, 4);for(int i = 0; i < 5; i++){cout<<a[i]<<" ";}getchar();return 0;}
对链表进行归并排序的代码如下:
struct node{int data;node * next;};/***对两个有序链表进行归并*/node *MergeList(node *head1, node *head2){node * tmp;if(head1 == NULL)return head2;if(head2 == NULL)return head1;if(head1->data < head2->data){tmp = head1;head1 = head1->next;}else{tmp = head2;head2 = head2->next;}tmp->next = MergeList(head1, head2);return tmp;}/***归并排序,参数为要排序的链表的头结点,函数返回值为排序后的链表的头结点*/node *MergeSort(node *head){if(head == NULL)return 0;node * r_head = head;node *head1 = head;node* head2 = head;while(head2->next != NULL && head2->next ->next!= NULL){head1 = head1->next;head2 = head2->next->next;}if(head1->next == NULL)/*说明只有一个节点,则返回该节点*/return r_head;head2 = head1->next;head1->next = NULL;head1 = head;/*函数MergeList是对两个有序链表进行归并,返回值是归并后的链表的头结点*/r_head = MergeList(MergeSort(head1), MergeSort(head2));return r_head;}