kalman滤波预测视频中红色小球位置
clear,clc
% 计算背景图像
Imzero = zeros(240,320,3);
for i = 1:5
Im{i} = double(imread(['F:\专业学习\书——MATLAB图像处理能力提高与应用案例\3.19 基于Kalman滤波的目标跟踪\DATA\',int2str(i),'.jpg']));
Imzero = Im{i}+Imzero;
end
Imback = Imzero/5;
[MR,MC,Dim] = size(Imback);
% Kalman滤波器初始化
R=[[0.2845,0.0045]',[0.0045,0.0455]'];
H=[[1,0]',[0,1]',[0,0]',[0,0]'];
Q=0.01*eye(4);
P = 100*eye(4);
dt=1;
A=[[1,0,0,0]',[0,1,0,0]',[dt,0,1,0]',[0,dt,0,1]'];
g = 6;
Bu = [0,0,0,g]';
kfinit=0;
x=zeros(100,4);
% 循环遍历所有图像
for i = 1 : 60
% 导入图像
Im = (imread(['DATA/',int2str(i), '.jpg']));
imshow(Im)
imshow(Im)
Imwork = double(Im);
%提取球的质心坐标及半径
[cc(i),cr(i),radius,flag] = extractball(Imwork,Imback,i);
if flag==0
continue
end
%用绿色标出球实际运动的位置
hold on
for c = -1*radius: radius/20 : 1*radius
r = sqrt(radius^2-c^2);
plot(cc(i)+c,cr(i)+r,'g.')
plot(cc(i)+c,cr(i)-r,'g.')
end
% Kalman器更新
if kfinit==0
xp = [MC/2,MR/2,0,0]'
else
xp=A*x(i-1,:)' + Bu
end
kfinit=1;
PP = A*P*A' + Q
K = PP*H'*inv(H*PP*H'+R)
x(i,:) = (xp + K*([cc(i),cr(i)]' - H*xp))';
x(i,:)
[cc(i),cr(i)]
P = (eye(4)-K*H)*PP
%用红色画出球实际的运动位置
hold on
for c = -1*radius: radius/20 : 1*radius
r = sqrt(radius^2-c^2);
plot(x(i,1)+c,x(i,2)+r,'r.')
plot(x(i,1)+c,x(i,2)-r,'r.')
end
pause(0.3)
end
% 画出球横纵坐标的位置
figure
plot(cc,'r*')
hold on
plot(cr,'g*')
%噪声估计
posn = [cc(55:60)',cr(55:60)'];
mp = mean(posn);
diffp = posn - ones(6,1)*mp;
Rnew = (diffp'*diffp)/5;
function [cc,cr,radius,flag]=extractball(Imwork,Imback,index) % 功能:提取图像中最大斑点的质心坐标及半径 % 输入:Imwork-输入的当前帧的图像;Imback-输入的背景图像;index-帧序列图像序号 % 输出:cc-质心行坐标;cr-质心列坐标;radius-斑点区域半径;flag-标志 cc = 0; cr = 0; radius = 0; flag = 0; [MR,MC,Dim] = size(Imback); % 将输入图像与背景图像相减,获得差异最大的区域 fore = zeros(MR,MC); fore = (abs(Imwork(:,:,1)-Imback(:,:,1)) > 10) ... | (abs(Imwork(:,:,2) - Imback(:,:,2)) > 10) ... | (abs(Imwork(:,:,3) - Imback(:,:,3)) > 10); foremm = bwmorph(fore,'erode',2); % 运用数学形态学去除微小的噪声 % 选择大的斑点对其周围进行标记 labeled = bwlabel(foremm,4); stats = regionprops(labeled,['basic']); [N,W] = size(stats); if N < 1 return end % 如果大的斑点的数量大于1,则用冒泡法进行排序 id = zeros(N); for i = 1 : N id(i) = i; end for i = 1 : N-1 for j = i+1 : N if stats(i).Area < stats(j).Area tmp = stats(i); stats(i) = stats(j); stats(j) = tmp; tmp = id(i); id(i) = id(j); id(j) = tmp; end end end % 确定并选取一个大的区域 if stats(1).Area < 100 return end selected = (labeled==id(1)); % 获得最大斑点区域的圆心及半径,并将标志置为1 centroid = stats(1).Centroid; radius = sqrt(stats(1).Area/pi); cc = centroid(1); cr = centroid(2); flag = 1; return
posted on 2015-07-19 22:18 nataliebky 阅读(441) 评论(1) 收藏 举报
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