package com.lw.leet4;
/**
* @ClassName:Solution
* @Description:
* Sort List
* Sort a linked list in O(n log n) time using constant space complexity.
* @Author LiuWei
* @Date 2014年8月18日上午10:17:45
* @Mail nashiyue1314@163.com
*/
/**
* Definition for singly-linked list.
* class ListNode {
* int val;
* ListNode next;
* ListNode(int x) {
* val = x;
* next = null;
* }
* }
*/
public class Solution {
public ListNode getMiddleNode(ListNode head){
ListNode slow = head;
ListNode fast = head;
while(fast.next != null && fast.next.next != null){
slow = slow.next;
fast = fast.next.next;
}
return slow;
}
public ListNode mergeList(ListNode list1,ListNode list2){
ListNode newHead = new ListNode(-1);
ListNode curNode = newHead;
while(list1 != null && list2 != null){
if(list1.val<= list2.val){
curNode.next = list1;
list1 = list1.next;
}
else{
curNode.next = list2;
list2 = list2.next;
}
curNode = curNode.next;
}
if(list1 == null){
curNode.next = list2;
}
else{
curNode.next = list1;
}
return newHead.next;
}
public ListNode sortList(ListNode head) {
if(head == null || head.next == null){
return head;
}
ListNode middleNode = getMiddleNode(head);
ListNode nextNode = middleNode.next;
middleNode.next = null;
return mergeList(sortList(head), sortList(nextNode));
}
public static void main(String[] args){
int[] arr = {4,19,14,5,-3,1,8,5,11,15};
ListNode head = new ListNode(arr[0]);
ListNode curr = head;
for(int i=1; i<arr.length; i++){
ListNode node = new ListNode(arr[i]);
curr.next = node;
curr = curr.next;
}
ListNode tmp = new Solution().sortList(head);
while(tmp != null){
System.out.println(tmp.val);
tmp = tmp.next;
}
}
}