实验5

 1 #include <stdio.h>
 2 #define N 5
 3 
 4  void input(int x[], int n);
 5  void output(int x[], int n);
 6  void find_min_max(int x[], int n, int *pmin, int *pmax);
 7  
 8  int main() {
 9      int a[N];
10      int min, max;
11  
12      printf("录入%d个数据:\n", N);
13      input(a, N);
14  
15      printf("数据是: \n");
16      output(a, N);
17  
18      printf("数据处理...\n");
19      find_min_max(a, N, &min, &max);
20  
21      printf("输出结果:\n");
22      printf("min = %d, max = %d\n", min, max);
23  
24      return 0;
25  }
26  
27  void input(int x[], int n) {
28      int i;
29  
30      for(i = 0; i < n; ++i)
31          scanf("%d", &x[i]);
32  }
33  
34  void output(int x[], int n) {
35      int i;
36      
37      for(i = 0; i < n; ++i)
38          printf("%d ", x[i]);
39      printf("\n");
40  }
41  
42  void find_min_max(int x[], int n, int *pmin, int *pmax) {
43      int i;
44      
45      *pmin = *pmax = x[0];
46  
47      for(i = 0; i < n; ++i)
48          if(x[i] < *pmin)
49              *pmin = x[i];
50          else if(x[i] > *pmax)
51              *pmax = x[i];
52  }

#include <stdio.h>
#define N 5

void input(int x[], int n);
void output(int x[], int n);
int *find_max(int x[], int n);

int main() {
    int a[N];
    int *pmax;

    printf("录入%d个数据:\n", N);
    input(a, N);

    printf("数据是: \n");
    output(a, N);

    printf("数据处理...\n");
    pmax = find_max(a, N);

    printf("输出结果:\n");
    printf("max = %d\n", *pmax);

    return 0;
}

void input(int x[], int n) {
    int i;

    for(i = 0; i < n; ++i)
        scanf("%d", &x[i]);
}

void output(int x[], int n) {
    int i;
    
    for(i = 0; i < n; ++i)
        printf("%d ", x[i]);
    printf("\n");
}

int *find_max(int x[], int n) {
    int max_index = 0;
    int i;

    for(i = 0; i < n; ++i)
        if(x[i] > x[max_index])
            max_index = i;
    
    return &x[max_index];
}

 1 #include <stdio.h>
 2  #include <string.h>
 3  #define N 80
 4  
 5  int main() {
 6      char s1[N] = "Learning makes me happy";
 7      char s2[N] = "Learning makes me sleepy";
 8      char tmp[N];
 9  
10      printf("sizeof(s1) vs. strlen(s1): \n");
11      printf("sizeof(s1) = %d\n", sizeof(s1));
12      printf("strlen(s1) = %d\n", strlen(s1));
13  
14      printf("\nbefore swap: \n");
15      printf("s1: %s\n", s1);
16      printf("s2: %s\n", s2);
17  
18      printf("\nswapping...\n");
19      strcpy(tmp, s1);
20      strcpy(s1, s2);
21      strcpy(s2, tmp);
22  
23      printf("\nafter swap: \n");
24      printf("s1: %s\n", s1);
25      printf("s2: %s\n", s2);
26  
27      return 0;
28  }

#include <stdio.h>
 #include <string.h>
 #define N 80
 
 int main() {
     char s1[N] = "Learning makes me happy";
     char s2[N] = "Learning makes me sleepy";
     char tmp[N];
 
     printf("sizeof(s1) vs. strlen(s1): \n");
     printf("sizeof(s1) = %d\n", sizeof(s1));
     printf("strlen(s1) = %d\n", strlen(s1));
 
     printf("\nbefore swap: \n");
     printf("s1: %s\n", s1);
     printf("s2: %s\n", s2);
 
    printf("\nswapping...\n");
     tmp = s1;
     s1 = s2;
     s2 = tmp;
 
 
     printf("\nafter swap: \n");
     printf("s1: %s\n", s1);
     printf("s2: %s\n", s2);
 
     return 0;
 }

#include <stdio.h>
 
 int main() {
     int x[2][4] = {{1, 9, 8, 4}, {2, 0, 4, 9}};
     int i, j;
     int *ptr1;     
     int(*ptr2)[4];
     printf("输出1: 使用数组名、下标直接访问二维数组元素\n");
      for (i = 0; i < 2; ++i) {
         for (j = 0; j < 4; ++j)
             printf("%d ", x[i][j]);
         printf("\n");
     }
 
     printf("\n输出2: 使用指针变量ptr1(指向元素)间接访问\n");
     for (ptr1 = &x[0][0], i = 0; ptr1 < &x[0][0] + 8; ++ptr1, ++i) {
         printf("%d ", *ptr1);
 
         if ((i + 1) % 4 == 0)
             printf("\n");
     }
                          
     printf("\n输出3: 使用指针变量ptr2(指向一维数组)间接访问\n");
     for (ptr2 = x; ptr2 < x + 2; ++ptr2) {
         for (j = 0; j < 4; ++j)
             printf("%d ", *(*ptr2 + j));
         printf("\n");
     }
 
     return 0;
 }

 1 #include <stdio.h>
 2 #define N 80
 3  
 4  void replace(char *str, char old_char, char new_char); 
 5  int main() {
 6      char text[N] = "Programming is difficult or not, it is a question.";
 7  
 8      printf("原始文本: \n");
 9      printf("%s\n", text);
10  
11      replace(text, 'i', '*');
12  
13      printf("处理后文本: \n");
14      printf("%s\n", text);
15  
16      return 0;
17  }
18  
19  void replace(char *str, char old_char, char new_char) {
20      int i;
21  
22      while(*str) {
23          if(*str == old_char)
24              *str = new_char;
25          str++;
26      }
27  }

#include <stdio.h>
#define N 80


char *str_trunc(char *str, char x) {
    char *p = str;  
    
    while (*p != '\0') {
        
        if (*p == x) {
            *p = '\0';  
            break;      
        }
        p++;  
    }
    return str;  句）
}

int main() {
    char str[N];
    char ch;
    char *result; 

   
    while (1) {
        printf("输入字符串：");
        scanf("%s", str);  
        printf("输入一个字符：");
        getchar(); 
        ch = getchar();

        printf("截断处理...\n");
        result = str_trunc(str, ch);  

        printf("截断处理后的字符串：%s\n\n", result);

        
        printf("是否继续？(y/n)：");
        ch = getchar();
        getchar();
        if (ch != 'y' && ch != 'Y') {
            break;
        }
    }

    return 0;
}

#include <stdio.h>
#include <string.h>
#define N 5

int check_id(char *str);

int main() {
    char *pid[N] = {"31010120000721656X",
                    "3301061996X0203301",
                    "53010220051126571",
                    "510104199211197977",
                    "53010220051126133Y"};
    int i;

    for (i = 0; i < N; ++i) {
        if (check_id(pid[i]))
            printf("%s\tTrue\n", pid[i]);
        else
            printf("%s\tFalse\n", pid[i]);
    }

    return 0;
}

int check_id(char *str) {
    int len = strlen(str);
    char *p = str;
    if (len != 18) return 0;
    while (p < str + 17) {
        if (*p < '0' || *p > '9') return 0;
        p++;
    }
    if ((*p >= '0' && *p <= '9') || *p == 'X' || *p == 'x' || *p == 'Y' || *p == 'y')
        return 1;
    else
        return 0;
}

#include <stdio.h>
 #define N 80
 
 void encoder(char *str, int n);
 void decoder(char *str, int n);
 
 int main() {
     char words[N];
     int n;
 
     printf("输入英文文本: ");
     gets(words);
 
     printf("输入n: ");
     scanf("%d", &n);
 
     printf("编码后的英文文本: ");
     encoder(words, n);
     printf("%s\n", words);
 
     printf("对编码后的英文文本解码: ");
     decoder(words, n);
     printf("%s\n", words);
 
     return 0;
 }
 
 void encoder(char *str, int n) {
     char *p = str;
     n = n % 26;
     while (*p != '\0') {
         if (*p >= 'a' && *p <= 'z') {
             *p = (*p - 'a' + n) % 26 + 'a';
         } else if (*p >= 'A' && *p <= 'Z') {
             *p = (*p - 'A' + n) % 26 + 'A';
         }
         p++;
     }
 }
 
 void decoder(char *str, int n) {
     char *p = str;
     n = n % 26;
     while (*p != '\0') {
         if (*p >= 'a' && *p <= 'z') {
             *p = (*p - 'a' - n + 26) % 26 + 'a';
         } else if (*p >= 'A' && *p <= 'Z') {
             *p = (*p - 'A' - n + 26) % 26 + 'A';
         }
         p++;
     }
 }

 1 #include <stdio.h>
 2 #include <string.h>
 3 
 4 int main(int argc, char *argv[]) {
 5     int i, j;
 6     char *tmp;
 7     if (argc < 2) {
 8         printf("请输入参数！\n");
 9         return 1;
10     }
11     for (i = 1; i < argc - 1; ++i) {
12         for (j = i + 1; j < argc; ++j) {
13             if (strcmp(argv[i], argv[j]) > 0) {
14                 tmp = argv[i];
15                 argv[i] = argv[j];
16                 argv[j] = tmp;
17             }
18         }
19     }
20     for (i = 1; i < argc; ++i) {
21         printf("hello, %s\n", argv[i]);
22     }
23     return 0;
24 }

posted @ 2025-12-12 15:11 nanxinyin 阅读(4) 评论(2) 收藏举报

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实验5

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