10 2016 档案

Linear Algebra lecture7 note
摘要：Computing the nullspace (Ax=0) Pivot variables-free variables Special solutions: rref( A)=R rank of A=the number of pivots=2 由上述矩阵行变换回代可得方程 我们自行给free 阅读全文
posted @ 2016-10-31 16:41 nanocare 阅读(274) 评论(0) 推荐(0)
Linear Algebra lecture6 note
摘要：Vector spaces and subspaces Column space of A solving Ax=b Null space of A Vector space requirements v+w and cv are in the space All combs cv+dw are i 阅读全文
posted @ 2016-10-31 13:03 nanocare 阅读(135) 评论(0) 推荐(0)
Linear Algebra Lecture5 note
摘要：Section 2.7 PA=LU and Section 3.1 Vector Spaces and Subspaces Transpose(转置） example: 特殊情况，对称矩阵（symmetric matrices),例如： 思考：R^R(R的转置乘以R)有什么特殊的？ 回答：alway 阅读全文
posted @ 2016-10-28 12:50 nanocare 阅读(154) 评论(0) 推荐(0)
Linear Algebra lecture4 note
摘要：Inverse of AB,A^(A的转置） Product of elimination matrices A=LU (no row exchanges) Inverse of AB,A^(A的转置）: Product of elimination matrices A=LU (no row ex 阅读全文
posted @ 2016-10-27 16:54 nanocare 阅读(239) 评论(0) 推荐(0)
Linear Algebra lecture3 note
摘要：Matrix multiplication(4 ways!) Inverse of A Gauss-Jordan / find inverse of A Matrix multiplication 1、点积法 2、matrix * column=comb of columns columns of 阅读全文
posted @ 2016-10-27 12:32 nanocare 阅读(214) 评论(0) 推荐(0)
Linear Algebra lecture 2 note
摘要：Lecture2 Elimination Inverses Permutation 消元法介绍（elimination）： 有方程组 提取系数，形成矩阵为： 消元的思想跟解方程组中先消除未知数的思路一致，通过数乘(multiply)和减法(substract)化简,化简过程为： 以上红框起来的数字叫 阅读全文
posted @ 2016-10-27 11:16 nanocare 阅读(396) 评论(0) 推荐(0)
Linear Algebra lecture1 note
摘要：Professor: Gilbert Strang Text: Introduction to Linear Algebra http://web.mit.edu/18.06 Lecture 1 contents: n linear equation, n unknowns Row picture 阅读全文
posted @ 2016-10-26 22:43 nanocare 阅读(129) 评论(0) 推荐(0)