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MariaDB ----单表查询

1>按一定条件查询某字段的数据 (where)

select  *  from students1 where  id>3; (  查询 id > 3 的数据)

#补充:

select * from students1  where id<3;

注意“ select * from  students1;  (此命令需谨慎使用, 数据量大可能导致爆内存)

2>给字段取别面并查询  ( 只是便于查询,没有做修改)

select   name  as  '姓名' ,age  as '年龄'  from  students1;

3> 给表取别名并查询

select   lichao.name   lichao.age  from  students1 as lichao;

4>查看某字段里的数据并消除重复的行 ( 重复的行不显示)

select   distinct  age  from students1;

5>查询id字段里  id大于4 而小于7的数据  (条件查询)  ( 满足 两个条件)

select  * from students  where  id>4 and id<7;

#补充

select * from  students1  where  age>30 and age<60;

#补充2

select  * from students1 where  age>40 && age<60;

6>条件查询(满足其中一个条件即可)( or)

select * from students1 where  id>5 or age<33;

#补充

select * from students1 where id>3 || age<33;

7>模糊查询

select * from studens1   where name like ’%杰%'; (查找name 类似于 杰的       杰前面和后面可以有任意字符)

#补充

select  * from  students1  where name like  ‘杰%';

#补充2

select * from students1 where name like '___'; ( 查找名字为三个字符的人名)  ( 一个下斜杠代表一个字符)

#补充3

select * from students1  where name like ’___%';  ( 至少三个字符)

8> 范围查询  ( 非连续型范围内)

select  * from students1 where  age in(22,19,44,45);

9>查询 age 在22与34 之间的人数

select   * from  students1 where  age betewn 22 and 34;

#也可以这样写

select  * from students1 where ( age between  22 and 34);

 #补充 ( 取反)

select * from students1  where age not between  22 and 34;

10>为空判断 、

select  * from  students1  where  high is null; ( 查询  high字段 为空的 某条(些)数据)

11>非空判断

select * from students1  where  high is not null;

12>排序

#1从小到大

select  * from students1  oder by age asc;  ( 按 age 的 从小 到大进行排序)

#2 从大到小

select * from students1 order by age desc; ( 按 age 的 从大到小进行排序)

&补充

select * from students1 where ( age between  22 and 46 )   order by age asc; (   把  年龄在 2246 岁之间的人 按年龄从小到大进行排序)

&补充2

select * from students1 where ( age  between 22 and 34 )  and  gander=1 order  by high  asc;

(  把  年龄在22 和 34 之间的男性 按 身高 从矮到高进行排列  )     (  包括 2234
View Code

 

 

&补充3

 查询年纪在18到34岁的女性,身高从高到矮排序,如果年纪相同的情况下按照身高从小到大排序

select * from  students1  where (age  between 18 and 34)  and   gender=2  order  by age desc, highasc;

 

13>聚合函数

&1 查询所有的男人 人数

select   count(*)  from students1   where  gender=1;

&2查询年纪最大的男人

select   max(age)  from  students1  where gender=1;

&3查询年纪最小的女人

select min(age) from students1  where gender=2;

&4 查询所有男人的年龄总和

select  sum(age) from students where gender=1;

&5查询所有男人的的平均年龄

select  sum(age)/count(*) from students1 where gender=1;

#补充  查询所有男人的的平均年龄

select  avg(age) from students1  where gender=1;

&6查询所有男人的的平均年龄 (切保留两位小数)

select  round(avg(age),2)  from students1 where gender=1;

14>分组

&1按照性别分组查找所有性别

select  gender  from students1  group by gender;

&2 查询每个性别的人数

select  gender,count(*)  from students1 group  by  gender;

#补充

select gender,sum(age)  from  students1  group by gender;

&3 查询gender组中的姓名

select gender,group_concat(name) from students  group by gender;

&4 查询每个性别平均年纪超过30岁的性别,以及姓名 having avg(age) > 40

select gender,group_concat(name) from students1 group  by gender   having avg(age)>40;

#查询每个性别平均年纪(且保留两位小数)

select  gender,group_concat(name),round (avg(age),2) from students1  group bt gender;

&5查询每种性别中的人数多于4个的组的信息

select gender,group_concat(name)  from students1 group  by gender having count(*)>4;

15>分页

#1分页显示,每页显示2条数据

setelct * from students1 limit 2;

#补充

按照身高从高到矮排序,查找出所有女性,并且分页显示,每页显示2条数据

select  * from  students1  where  gender  order desc  limit  2;  

#补充2

按照年纪从小到大排序,查找出所有男性,并且分页显示,每页显示3 条数据 (年纪若相同,则按身高从高到低排序)

select * from students where  gender=1  order by age asc,high desc  limit 0,3

 

 

posted on 2019-05-18 00:06  lichaoyx  阅读(670)  评论(0编辑  收藏  举报

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