实验四 8086标志寄存器及中断
一、
assume cs:code, ds:data
data segment
x dw 1020h, 2240h, 9522h, 5060h, 3359h, 6652h, 2530h, 7031h
y dw 3210h, 5510h, 6066h, 5121h, 8801h, 6210h, 7119h, 3912h
data ends
code segment
start:
mov ax, data
mov ds, ax
mov si, offset x
mov di, offset y
call add128
mov ah, 4ch
int 21h
add128:
push ax
push cx
push si
push di
sub ax, ax
mov cx, 8
s: mov ax, [si]
adc ax, [di]
mov [si], ax
inc si
inc si
inc di
inc di
loop s
pop di
pop si
pop cx
pop ax
ret
code ends
end start
(1)不能替换,因为add指令会改变CF的值,使进位出错

(2)

二、
assume cs:code, ds:data data segment str db 80 dup(?) data ends code segment start: mov ax, data mov ds, ax mov si, 0 s1: mov ah, 1 int 21h mov [si], al cmp al, '#' je next inc si jmp s1 next: mov ah, 2 mov dl, 0ah int 21h mov cx, si mov si, 0 s2: mov ah, 2 mov dl, [si] int 21h inc si loop s2 mov ah, 4ch int 21h code ends end start

(1)作用:输入字符到al,存入[si],和'#'比较,相等进入next,不相等顺序执行
(2)输出换行符
(3)输出字符si次,由于最后一次si没有增加,所以'#'不输出
三、
assume ds:data, cs:code, ss:stack
data segment
x dw 91, 792, 8536, 65535, 2021, 0
len equ $ - x
data ends
stack segment
db 16 dup(0)
stack ends
code segment
start:
mov ax, data
mov ds, ax
mov ax, stack
mov ss, ax
mov sp, 16
mov di, offset x
mov cx, len/2 ; len/2
foreach:
mov ax, word ptr ds:[di]
push cx
call printNumber
pop cx
mov ah, 2
mov dl, 20h
int 21h
add di, 2
loop foreach
mov ah, 4ch
int 21h
;ax:
printNumber:
mov bx, 0
num:
mov dx, 0
mov bp, 10
div bp;dxax/bp
push dx;
inc bx;
cmp ax, 0
je next
jmp num
next:
mov cx, bx;
print:
pop dx
add dl, 30h;
mov ah, 2
int 21h
loop print
ret
code ends
end start

四、
data segment
str1 db "assembly language, it's not difficult but tedious"
len equ $ - str1
data ends
stack segment
db 16 dup(0)
stack ends
code segment
assume cs:code,ds:data,ss:stack
start:
mov ax,data
mov ds,ax
mov si,offset str1
mov cx,len
call strupr
mov ah,4ch
int 21h
strupr:
s:
mov al,ds:[si]
cmp al,'a'
jb next
cmp al,'z'
ja next
and al,0dfh;1101 1111
mov ds:[si],al
next:
inc si
loop s
ret
code ends
end start


五、
assume cs:code, ds:data data segment str1 db "yes", '$' str2 db "no", '$' data ends code segment start: mov ax, data mov ds, ax mov ah, 1 int 21h ; 从键盘输入字符 mov ah, 2 mov bh, 0 mov dh, 24 ; 设置光标位置在第24行 mov dl, 70 ; 设置光标位置在第70列 int 10h ; 设置光标位置 cmp al, '7' je s1 mov ah, 9 mov dx, offset str2 int 21h ; 显示标号str2处的字符串 jmp over s1: mov ah, 9 mov dx, offset str1 int 21h ; 显示标号str2处的字符串 over: mov ah, 4ch int 21h code ends end start

程序功能:
将从键盘输入的字符与7进行比较,如果相同,则输出数据段的str1标号处数据yes;
如果不相同,则输出数据段的str2标号处数据no。
六、
(1)
assume cs:code
code segment
start:
; 42 interrupt routine install code
mov ax, cs
mov ds, ax
mov si, offset int42 ; set ds:si
mov ax, 0
mov es, ax
mov di, 200h ; set es:di
mov cx, offset int42_end - offset int42
cld
rep movsb
; set IVT(Interrupt Vector Table)
mov ax, 0
mov es, ax
mov word ptr es:[42*4], 200h
mov word ptr es:[42*4+2], 0
mov ah, 4ch
int 21h
int42:
jmp short int42_start
str db "welcome to 2049!"
len equ $ - str
; display string "welcome to 2049!"
int42_start:
mov ax, cs
mov ds, ax
mov si, 202h
mov ax, 0b800h
mov es, ax
mov di, 24*160 + 32*2
mov cx, len
s: mov al, [si]
mov es:[di], al
mov byte ptr es:[di+1], 2
inc si
add di, 2
loop s
iret
int42_end:
nop
code ends
end start
(2)
assume cs:code
code segment
start:
int 42
mov ah, 4ch
int 21h
code ends
end start

运行程序过后,通过实现中断,在屏幕底部的中间成功显示绿色的“welcome to 2049!”。在程序exe6_1.asm中,先将si赋值为标号int42的地址,将di赋值为200h,然后利用rep movsb指令,将int42到int42_end的指令复制到0:200h开始的连续内存空间,接着设置中断向量表,使得exe6_2.asm中通过int42可以跳转到中断处理程序。标号int42到int42_end的指令则实现了在屏幕第0页的最后一行中间打印绿色的“welcome to 2049!”

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