leetCode热题100-35、36题

35、二叉树的中序遍历

给定一个二叉树的根节点 root ，返回 它的 中序 遍历 。

/**
 * Definition for a binary tree node.
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode() {}
 *     TreeNode(int val) { this.val = val; }
 *     TreeNode(int val, TreeNode left, TreeNode right) {
 *         this.val = val;
 *         this.left = left;
 *         this.right = right;
 *     }
 * }
 */
class Solution {
    public List<Integer> inorderTraversal(TreeNode root) {
        List<Integer> res = new ArrayList<Integer>();
        inorder(root,res);
        return res;
    }

    public void inorder(TreeNode root,List<Integer> res) {
        if (root == null) {
            return;
        }
        inorder(root.left,res);
        res.add(root.val);
        inorder(root.right,res);
    }
}

36、二叉树的最大深度

二叉树的 最大深度

/**
 * Definition for a binary tree node.
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode() {}
 *     TreeNode(int val) { this.val = val; }
 *     TreeNode(int val, TreeNode left, TreeNode right) {
 *         this.val = val;
 *         this.left = left;
 *         this.right = right;
 *     }
 * }
 */
// 深度优先遍历
class Solution {
    public int maxDepth(TreeNode root) {
        if (root == null) {
            return 0;
        }else {
            int left = maxDepth(root.left);
            int right = maxDepth(root.right);
            return Math.max(left,right) + 1;
        }
    }
}

// 广度优先遍历
class Solution {
    public int maxDepth(TreeNode root) {
        if (root == null) {
            return 0;
        }
        Queue<TreeNode> queue = new LinkedList<TreeNode>();
        queue.offer(root);
        int ans = 0;
        while (!queue.isEmpty()) {
            int size = queue.size();
            while (size > 0) {
                TreeNode node = queue.poll();
                if (node.left != null) {
                    queue.offer(node.left);
                }
                if (node.right != null) {
                    queue.offer(node.right);
                }
                size--;
            }
            ans++;
        }
        return ans;
    }
}