冒泡排序

int a[] = { 23,1,55,7,4,2 };
int n = 6, i, j, temp;
for ( i = 1; i < 6; i++)   //趟数
{
	for ( j = 0; j <n-i; j++)   //每趟的顺序比较
	
		if (a[j] > a[j + 1])
		{	temp = a[j];
		    a[j] = a[j + 1];
		    a[j + 1] = temp;
		}

}
for ( i = 0; i < 6; i++)
{
	printf("%5d", a[i]);
posted @ 2022-09-30 16:33  手抄面来啰  阅读(24)  评论(0)    收藏  举报