Java数组的简单概括
Java数组
-
定义:相同类型数据的有序集合
-
声明:
int[] nums;
- 创建:
nums = new int[10];
- 声明加创建:(动态初始化(包含默认初始化))
int[] nums= new int[10];
- 获取数组长度:
int a = nums.length;
- 静态初始化:
int[] nums= {1,2,3,4,5,6,7,8};
- 数组的基本特点
- 长度确定
- 元素类型一致
- 元素类型不限
- 数组变量为引用类型,数组可看成对象,数组中的每个元素相当于该对象的成员变量
- 数组本身就是对象,Java保存在堆中
- 数组边界:[0,length-1]
数组的使用
-
For-Each循环
int[] a={1,2,3,4,5,6,7}; for (int i : a) { System.out.println(i); } -
数组做方法入参
public static void main(String[] args) { int[] a={1,2,3,4,5,6,7}; printArray(a); } public static void printArray(int[] arrays){ for (int i = 0; i < arrays.length; i++) { System.out.println(arrays[i]); } } -
数组做返回值(反转数组)
public static void main(String[] args) { int[] arrays={1,2,3,4,5,6,7}; printArray(reverse(arrays)); } //数组做方法入参 public static void printArray(int[] arrays){ for (int i = 0; i < arrays.length; i++) { System.out.println(arrays[i]); } } //数组反转 public static int[] reverse(int[] arrays){ int[] result = new int[arrays.length]; for (int i = 0,j=arrays.length-1; i < arrays.length; i++,j--) { result[j]=arrays[i]; } return result; }
多维数组
-
定义
int[][] arrays = {{1,2},{2,3},{3,4},{4,5}};//二维数组 -
遍历二维数组
int[][] arrays = {{1,2},{2,3},{3,4},{4,5}}; for (int i = 0; i < arrays.length; i++) { for (int j = 0; j < arrays[i].length; j++){ System.out.println(arrays[i][j]); } }
Arrays类
- 打印数组元素:Arrays.toString()
- 自动排序(升序):Arrays.sort()
- 等
冒泡排序
import java.lang.reflect.Array;
import java.util.Arrays;
public class Demo {
public static void main(String[] args) {
int[] array = {7,4,3,56,5,2,9};
int[] sort = sort(array);
System.out.println(Arrays.toString(sort));
}
public static int[] sort(int[] array){
int temp = 0;
for (int i = 0; i < array.length-1; i++) {
for (int j = 0; j < array.length-1-i; j++) {
if (array[j]<array[j+1]){
temp = array[j];
array[j] = array[j+1];
array[j+1] = temp;
}
}
}
return array;
}
}
稀疏数组
public class Demo99 {
public static void main(String[] args) {
//创建一个棋盘 11*11 0:没有棋子 ,1:黑棋 ,2:白棋
int[][] array = new int[11][11];
array[1][2]=1;
array[2][3]=2;
System.out.println("输出原始的数组");
for (int[] ints : array) {
for (int anInt : ints) {
System.out.print(anInt+"\t");
}
System.out.println(" ");
}
System.out.println("====================================");
//生成稀疏数组
//遍历有效值,得出稀疏数组的行数
int sum = 0;
for (int[] ints : array) {
for (int anInt : ints) {
if (anInt!=0){
sum++;
}
}
}
System.out.println("有效值为:"+sum);
//创建稀疏数组
int[][] array2 = new int[sum+1][3];
array2[0][0]=array.length;
array2[0][1]=array.length;
array2[0][2]=sum;
int count = 0;
for (int i = 0; i < array.length; i++) {
for (int j = 0; j < array.length; j++) {
if (array[i][j]!=0){
count++;
array2[count][0]=i;
array2[count][1]=j;
array2[count][2]=array[i][j];
}
}
}
//遍历输出稀疏数组
for (int[] ints : array2) {
for (int anInt : ints) {
System.out.print(anInt+"\t");
}
System.out.println(" ");
}
System.out.println("=====================================");
//还原数组
int[][] array3 = new int[array2[0][0]][array2[0][1]];
for (int i = 1; i < array2.length; i++) {
array3[array2[i][0]][array2[i][1]]=array2[i][2];
}
for (int[] ints : array3) {
for (int anInt : ints) {
System.out.print(anInt+"\t");
}
System.out.println(" ");
}
}
}
----------------------------输出------------------------------------
输出原始的数组
0 0 0 0 0 0 0 0 0 0 0
0 0 1 0 0 0 0 0 0 0 0
0 0 0 2 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0
====================================
有效值为:2
11 11 2
1 2 1
2 3 2
=====================================
0 0 0 0 0 0 0 0 0 0 0
0 0 1 0 0 0 0 0 0 0 0
0 0 0 2 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0
0 0 0 0 0 0 0 0 0 0 0

浙公网安备 33010602011771号